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2 years ago

Plz help due tomorrow if correct ill give brailiest

Mathematics

2 answers:

meriva2 years ago

5 0

Answer:

Division (Hope this helps)

Step-by-step explanation:

algol132 years ago

4 0

Division because first you solve whats in the parentheses them you solve and last you divide

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Is the triangle obtuse, acute, equilateral or right?

Stells [14]

9514 1404 393

Answer:

obtuse

Step-by-step explanation:

The law of cosines tells you ...

b² = a² +c² -2ac·cos(B)

Substituting for a²+c² using the given equation, we have ...

b² = b²·cos(B)² -2ac·cos(B)

We can subtract b² to get a quadratic in standard form for cos(B).

b²·cos(B)² -2ac·cos(B) -b² = 0

Solving this using the quadratic formula gives ...

$\cos(B)=\dfrac{-(-2ac)\pm\sqrt{(-2ac)^2-4(b^2)(-b^2)}}{2b^2}\\\\\cos(B)=\dfrac{ac}{b^2}\pm\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}$

The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...

$\cos(B)=\dfrac{ac}{b^2}-\sqrt{\left(\dfrac{ac}{b^2}\right)^2+1}$

The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.

4 0

3 years ago

Read 2 more answers

At a local restaurant the amount of time that customers have to wait for their food is normally distributed with a mean of 26 mi

konstantin123 [22]

Answer:http://avconline.avc.edu/jdisbrow/ma115/Practice%20Test%203%20with%20answers.pdf

Step-by-step explanation:

you welcome

6 0

3 years ago

Solve the right triangle below. Round all your answers to the nearest tenth. Measure of angle Z = ______

valentina_108 [34]

Answer:

$Measure \: of \: angle \: z = \boxed{ \tt{ 19.5\degree}}$

7 0

2 years ago

Start at (12, 3). Move 2 units right and 7 units up. Where do you end up?

Korolek [52]

Answer: (10, 10)

Step-by-step explanation: well if you say start at (12, 3) move 7 units up then 3 units right then it would make it easier to figure it out cus as you can see start at 3 and go up 7 it would stop at 10 then if you go over 2 from 12 it would stop at 10

6 0

3 years ago

Find a solution of the quadratic equation.6x squared + 7x + 2 =0

worty [1.4K]

Given the equation:

$6x^2+7x+2=0$

We will use the following rule to find the solution to the equation:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

From the given equation: a = 6, b = 7, c = 2

So,

$\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}$

So, the answer will be option B) x = -1/2, -2/3

5 0

1 year ago