Which sets of ordered pairs show equivalent ratios? Check all that apply.

-2(x-4)=-16 SOLVE FOR X!!

Andrej [43]

Answer:

x = 12

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Step-by-step explanation:

Step 1: Define equation

-2(x - 4) = -16

Step 2: Solve for x

Distribute -2: -2x + 8 = -16
Isolate x term: -2x = -24
Isolate x: x = 12

Step 3: Check

Plug in x to verify it's a solution.

Substitute: -2(12 - 4) = -16
Subtract: -2(8) = -16
Multiply: -16 = -16

Here we see that -16 does indeed equal -16.

∴ x = 12 is a solution of the equation.

6 0

3 years ago

Name 5 decimal numbers that are between 4.78 and 4.79. Explain your answer.

Karolina [17]

4.781, 4.782,4.783,4.784,4.785

I can't explain though:(

6 0

3 years ago

Read 2 more answers

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}$

Distribute -x through the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)}$

Using ${a}^{2} - {b}^{2} = (a + b)(a - b)$ , simplify the product

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)}$

Collect like terms

$\frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)}$

Subtract the numbers

$\frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)}$

Distribute x through the parentheses

$\frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x}$

Write 7x as a sum

$\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }$

Factor out X from the expression

$\frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x}$

Factor out 2 from the expression

$\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }$

Factor out x + 5 from the expression

$\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$

Hope this helps...

Best regards!!

6 0

3 years ago

Read 2 more answers

The area of a rectangular pool is given by the trinomial 2y^2-y-3. What are the possible dimensions of the pool? Use factoring.

RSB [31]

Answer:

(2y−3)(y+1) hope this helps!

7 0

2 years ago

15 pts plz help

RoseWind [281]

Answer:

two the right then below

Step-by-step explanation:

6 0

3 years ago