I need help please asap
1 answer:
You might be interested in
Answer:
Now we can set up the derivate equal to 0 and we have:
And solving for t we got:
For the second derivate respect the time we got:
So then we can conclude that t = 4.206 is a maximum for the function.
And the corresponding height would be:
So the maximum occurs at t = 4.206 s and with a height of 135.468 m
Step-by-step explanation:
For this case we have the following function:
In order to maximize this function we need to take the first derivate respect the time and we have:
Now we can set up the derivate equal to 0 and we have:
And solving for t we got:
For the second derivate respect the time we got:
So then we can conclude that t = 4.206 is a maximum for the function.
And the corresponding height would be:
So the maximum occurs at t = 4.206 s and with a height of 135.468 m
Answer:
42.64°
Step-by-step explanation:
Note: A rhombus has all its sides equal, its opposite angle are equal, its has bigger and smaller diagonal, diagonal bisect the angles and diagonal bisect each other.
From the diagram attached,
sinθ = opposite/adjacent
sinθ = 4/11
θ = sin⁻¹(4/11)
θ = 21.32
Therefore, from the diagram,
The smaller angle of the rhombus = 2θ
The smaller angle of the rhombus = (2×21.32)
The smaller angle of the rhombus = 42.64°
