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Kruka [31]
3 years ago
14

What’s the area/volume?

Mathematics
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

pls what shape is that .

You might be interested in
Las+salchichas+vienen+en+paquetes+de+6+y+los+panes+para+panchos+se+envasan+en+paquetes+de+8+unidades+¿Es+cierto+que+si+se+prepar
vovikov84 [41]

Answer:

Es cierto se usan 16 paquetes de salchichas y 12 paquetes de panes para pancho.

Step-by-step explanation:

Lo que debemos hacer en este caso es dividir la cantidad total de panchos primero por la cantidad de unidades de salchichas que vienen en su paquete y segundo por la cantidad de unidades de panes para panchos que vienen en su paquete, si el resultado nos da un numero entero podemos decir que usa una cantidad completa de paquetes de salchichas y de panes:

96/6 = 16

96/8 = 12

Es decir que para 96 panchos se usan 16 paquetes de salchichas y 12 paquetes de panes para pancho, por lo tanto es cierto.

8 0
3 years ago
Check
algol [13]

Answer: Option A is the correct answer, y = x + 2

y - 3 = x-1

Step-by-step explanation:

6 0
2 years ago
Jim earns $1,600 per month after taxes. He is working on his budget and has the first three categories finished. Housing $576 Fo
Afina-wow [57]

B.

He has used the highest recommended percentages to calculate the amounts for the three categories.

5 0
3 years ago
Read 2 more answers
After the party, Jane washed half of the glasses. Alex washed half of the remaining glasses, and then Sasha Alex washed half of
andreyandreev [35.5K]

Answer:

16

Step-by-step explanation:

Let's take a look.

So we have 3*2*2*2*2=48 glasses

if half used 2 and other half used 1... we have a sum of 2+1=3

so 48/3 = 16

4 0
3 years ago
Find the exact value of the following expression (without using a calculator): tan(Sin^-1 x/2)
Sati [7]

Answer:

tan(Sin^-1 x/2)=  \frac{x/2}{\sqrt{1-x^{2}/4 } }

Step-by-step explanation:

Let sin^-1 x/2= θ

then sinθ= x/2

on the basis of unit circle, we have a triangle with hypotenuse of length 1,   one side of length x/2 and opposite angle of θ.

          tan(Sin^-1 x/2) = tanθ

           tanθ= sinθ/cosθ

as per trigonometric identities cosθ= √(1-sin^2θ)

           tanθ= sinθ/ √(1-sin^2θ)

substituting the value sinθ=x/2 in the above equation

             tanθ= \frac{x/2}{\sqrt{1-x^{2}/4 } }

now substituting the value sin^-1 x/2= θ in above equation

             tan(sin^-1 x/2) =  \frac{x/2}{\sqrt{1-x^{2}/4 } }

!

3 0
3 years ago
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