Question

What is an equation of the line that passes through the point (3,-1) and (8, 9)?

Answer 1

Answer:

4) y = 2x - 7

Step-by-step explanation:

First we have to find the slope by using the following formula....

let (3, - 1) be $(x_{1}, y_{1} )$, let (8, 9) be $(x_{2} ,y_{2} )$, and m be the slope, then....

$m = \frac{y_{2} -y_{1} }{x_{2} - x_{1} } = \frac{9 + 1}{8 - 3} = \frac{10}{5} = 2$

Now that we know the slope we can find the equation of the function by using point-slope for of the function which look like this.....

$y -y_{1} = m(x - x_{1} )\\y + 1 = 2(x - 3)\\y + 1 = 2x - 6\\y = 2x - 7$