\#17 and 18 only/ ty for helping don’t use for points
1 answer:
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Area of the electronic board is 9000 cm2
Step-by-step explanation:
Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.
The Electronic board always seems like a rectangular shape
Length= scale÷Actual = 5/36 = 5×36 = 180cm
Width=scale÷Actual = 1/50 = 1×50 = 50cm
Area of Rectangle = legnth × width
= 180cm × 50cm = 9000 cm2
Area of the electronic board is 9000 cm2
<u>Answer:</u>
Below!
<u>Step-by step explanation:</u>
<u>We know that:</u>
- 400 + 850 + m = 1500
<u>Solution of Question A:</u>
<u>Percent of children: Total children/Total attendance</u>
- => 400/1500
- => 4/15
- => 0.27 (Rounded to nearest hundredth)
- => 0.27 x 100
- => 27%
<u>Hence, the percent of children is about 27%.</u>
<u>Solution of Question B:</u>
<u>Percent of women: Total women/Total attendance</u>
- => 850/1500
- => 85/150
- => 17/30
- => 17/30 x 100
- => 17/3 x 10
- => 170/3
- => 56.67%
<u>Hence, the percent of women is 56.67%.</u>
<u>Solution of Question C:</u>
- 400 + 850 + m = 1500
- => 1250 + m = 1500
- => m = 1500 - 1250
- => m = 250
<u>Percent of men: Total men/Total attendance</u>
- => 250/1500
- => 1/6
- => 0.17 (Rounded to nearest hundredth)
- => 0.17 x 100
- => 17%
<u>Hence, the percent of men is about 17%</u>
Hoped this helped.