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satela [25.4K]
3 years ago
13

PLEASE HELP MEEE AM BEING TIMED

Mathematics
1 answer:
Masteriza [31]3 years ago
7 0

Answer:

4 g/mL

Step-by-step explanation:

ρ =   m/ V

=   60 gram/ 15 milliliter

=  4 gram/milliliter

You might be interested in
Mark and Don are planning to sell each other their marble collections at a garage sale. If Don has 1 more than 3 times the numbe
Volgvan

Answer: Mark has 28 marbles while Don has 85 marbles.

Step-by-step explanation:

Let x represent the number of marbles that Mark has.

Let y represent the number of marbles that Don has.

If Don has 1 more than 3 times the number of marbles Mark has, it means that

y = 3x + 1

The total number of marbles is 113. It means that

x + y = 113- - - - - - - - - - - - 1

Substituting y = 3x + 1 into equation 1, it becomes

x + 3x + 1 = 113

4x + 1 = 113

4x = 113 - 1 = 112

x = 112/4

x = 28

y = 3x + 1 = 3 × 28 + 1

y = 85

4 0
3 years ago
The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil
satela [25.4K]

The length of pencil A is 5 cm

<em><u>Solution:</u></em>

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

<em><u>The total length of pencils A, B and C is 29 cm</u></em>

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

<em><u>Pencil A is 11 cm shorter then pencil B</u></em>

x = y - 11 ------- eqn 2

<em><u>Pencil B is twice as long a pencil C</u></em>

y = 2z

z = \frac{y}{2} ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16

<em><u>Substitute y = 16 in eqn 2</u></em>

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0
3 years ago
A regression equation that predicts the price of homes in thousands of dollars is t = 24.6 + 0.055x1 - 3.6x2, where x2 is a dumm
AveGali [126]

Answer:

a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

Step-by-step explanation:

For the same home (x1 is the same), x2 = 1 if it is on a busy street and x2 = 0 if it is not on a busy street. If x2 = 1, the value of 't' decreases by 3.6 when compared to the value of 't' for x2=0. Since 't' is given in thousands of dollars, when a home is on a busy street, its value decreases by 3.6 thousand dollars.

t(x1, 0)= 24.6 + 0.055x1\\t(x1, 1) = 24.6 + 0.055x1 - 3.6\\t(x1, 1) = t(x1, 0) - 3.6

Therefore, the answer is a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

8 0
3 years ago
A street lamp is 14 ft tall. On a sunny day, the street lamp casts a shadow 8 ft long. What is
saw5 [17]

Answer:

60.25≈60.3°

Step-by-step explanation:

tanФ=14/8=1.75

Ф=arctan=1.75

tan-1  

60.25≈60.3

8 0
3 years ago
Subtract 3/y-2 - 1/y+3
Helen [10]
To subtract fractions, we need a common denominator.

\frac{3}{y-2} - \frac{1}{y+3}

the common denominator will be (y-2)(y+3)

\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}
\frac{3y + 9 - y + 2}{(y-2)(y+3)}
\frac{2y + 11}{(y-2)(y+3)}

The answer above will be the simplified form.
3 0
3 years ago
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