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vlabodo [156]
3 years ago
7

The school bus Evie rides is scheduled to arrive at her stop at 8:20 a.m. each day. The table below shows the actual arrival tim

es of the bus for several days that were randomly selected over the past few months. Based on these data, what is the probability that the bus will arrive at Evie's stop before 8:20 a.m. tomorrow?
I have an answer I just want to know how other people would do it..

Mathematics
2 answers:
saveliy_v [14]3 years ago
6 0
Im not sure what the answer is but dont open the link its a virus
wolverine [178]3 years ago
3 0

Answer:

uh yeah i dont really do mud

Step-by-step explanation:

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Pls help this is my last attempt to get it right before I fail.
TEA [102]
The answer is D. SF is .4
5 0
3 years ago
Read 2 more answers
What are all the ways to make 37 with tens and ones?
Sunny_sXe [5.5K]
3 tens
7 ones

This is the same as 30+7 which is 37
5 0
3 years ago
Which describes how square S could be transformed to square S prime in two steps? Assume that the center of dilation is the orig
gayaneshka [121]

Answer:

The correct option is;

A dilation by a scale factor of Two-fifths and then a translation of 3 units up

Step-by-step explanation:

Given that the coordinates of the vertices of square S are

(0, 0), (5, 0), (5, -5), (0, -5)

Given that the coordinates of the vertices of square S' are

(0, 1), (0, 3), (2, 3), (2, 1)

We have;

Length of side, s, for square S is s = √((y₂ - y₁)² + (x₂ - x₁)²)

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates of two consecutive vertices

When (x₁, y₁) = (0, 0) and (x₂, y₂) = (5, 0), we have;

s = √((y₂ - y₁)² + (x₂ - x₁)²) = s₁ = √((0 - 0)² + (5 - 0)²) = √(5)² = 5

For square S', where (x₁, y₁) = (0, 1) and (x₂, y₂) = (0, 3)

Length of side, s₂, for square S' is s₂ = √((3 - 1)² + (0 - 0)²) = √(2)² = 2

Therefore;

The transformation of square S to S' involves a dilation of s₂/s₁ = 2/5

The after the dilation (about the origin),  the coordinates of S becomes;

(0, 0) transformed to (remains at) (0, 0) ....center of dilation

(5, 0) transformed to (5×2/5, 0) = (2, 0)

(5, -5) transformed to (2, -2)

(0, -5) transformed to (0, -2)

Comparison of (0, 0), (2, 0), (2, -2), (0, -2) and (0, 1), (0, 3), (2, 3), (2, 1) shows that the orientation is the same;

For (0, 0), (2, 0), (2, -2), (0, -2) we have;

(0, 0), (2, 0) the same y-values, (∴parallel to the x-axis)

(2, -2), (0, -2) the same y-values, (∴parallel to the x-axis)

For (0, 1), (0, 3), (2, 3), (2, 1) we have;

(0, 3), (2, 3) the same y-values, (∴parallel to the x-axis)

(0, 1), (2, 1) the same y-values, (∴parallel to the x-axis)

Therefore, the lowermost point closest to the y-axis in (0, 0), (2, 0), (2, -2), (0, -2) which is (0, -2) is translated to the lowermost point closest to the y-axis in (0, 1), (0, 3), (2, 3), (2, 1) which is (0, 1)

That is (0, -2) is translated to (0, 1) which shows that the translation is T((0 - 0), (1 - (-2)) = T(0, 3) or 3 units up

The correct option is therefore a dilation by a scale factor of Two-fifths and then a translation of 3 units up.

7 1
3 years ago
2(x-+2)+4=6x-4(-1+x)
sertanlavr [38]

2x-4+4=6x+4-4x

2x=2x+4

c there is no solution

8 0
3 years ago
Read 2 more answers
Hewp..Pls
timofeeve [1]

Answer:

2y+4x=12

2*1+4*8=12

2+32=12

35=12

7 0
3 years ago
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