Two side length of a triangle are given as 9 cm and 5 cm. What could be the length of its third side?

2 answers:

5 0

Answer: Two sides are given 5 cm and 9 cm. .Therefore, the third side can not be greater than or equal to (9+5)=14 cm and it can not be less than or equal to (9–5)=4 cm

Step-by-step explanation:

Please Give me brainliest

Lana71 [14]3 years ago

5 0

Answer:

Step-by-step explanation:

the length to the third side can be

a) a^2+b^2=c^2

a=9, b=5

c^2=81+25=106

c=sqrt106=10.29

a=5, c=9

b^2=c^2-a^2

b^2=81-25=56

b=sqrt56=7.48

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The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean

Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .