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VLD [36.1K]
3 years ago
5

What is the solution to the system of equations? I will mark the brainliest answer

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0
Ok so let us label our equations first
1- 3x+2y+z=7
2- 5x+5y+4z=3
3- 3x+2y+3z=1
subtracting equation 3 from equation 1
3x+2y+3z=1
(-). 3x+2y+z= 7
----------------------
2z=-6----->z=-3
since we already chose equation 1 and 3 we must involve equation 2
substituting the value if z in the second equation
5x+5y-12=3
5x+5y=15
choosing either the first or the third
3x+2y-3=7
3x+2y=10
solving the system
5x+5y=15
3x+2y=10
multipling the first equation by 2 and the second equation by 5
10x+10y=30
15x+10y=50
subtracting the two equations
-5x=-20--->x=4 substituting for the value of x
40+10y=30--->10y=-10y--->y=-1
so our soultion is x=4,y=-1,z==-3 or (4,-1,-3)








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Answer:

Ques 1:

Let us consider the system of equations,

2x+y=3 and 3x-y=2

It is known that 'The intersection points of the graphs of the system of equations are the solutions of the system of equations'.

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Ques 2:

We have the functions, f(x)= 2x+1 and g(x)= 2x^2+1.

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Answer:

6/5m

or

1 1/5m

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According to a recent New York Times poll, 25% of the public have responded to a telephone call-in
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Answer:

Probability that exactly two people out of a randomly  chosen group of five people have responded to a telephone call-in poll is 0.264.

Step-by-step explanation:

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Also, five people have people have been randomly selected.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......

where, n = number trials (samples) taken = 5 people

           r = number of success = exactly two

           p = probability of success which in our question is probability that

                 public have responded to a telephone call-in  poll, i.e; p = 25%

<em><u>Let X = Number of people who have responded to a telephone call-in  poll</u></em>

So, X ~ Binom(n = 5, p = 0.25)

Now, probability that exactly two people out of group of five people have responded to a telephone call-in poll is given by = P(X = 2)

                P(X = 2)  =  \binom{5}{2} \times 0.25^{2} \times (1-0.25)^{5-2}

                               =  10 \times 0.25^{2}  \times 0.75^{3}

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<em>Therefore, the probability that exactly two people out of a randomly  chosen group of five people have responded to a telephone call-in poll is 0.264.</em>

3 0
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