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3 years ago

The diagram shows a sector of a circle radius 11 cm.

Mathematics

1 answer:

nadya68 [22]3 years ago

4 0

Answer:

Perimeter of sector is 47.93 cm which is greater than 47.5 cm

Step-by-step explanation:

Mathematically, the perimeter of a sector is length of the arc plus 2 radii

The length of the arc is;

theta/360 * 2 * pi * r

where theta is the angle subtended by the arc at the center of the circle

Thus, we have

135/360 * 2 * 22/7 * 11 = 25.93

Add 2 radii = 25.93 + 2(11) = 47.93 cm

This is greater than what we are asked to calculate and thus we have shown what we are asked to show

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2(x + 2) + 2 = 2(x + 3) + 1

Maslowich

Answer:

No solution

Step-by-step explanation:

5(x + 4) – x = 4(x + 5) – 1

x = ?

Solution:

5(x+4)−x=4(x+5)−1

Apply Distributive property:

(5)(x)+(5)(4)−x=(4)(x)+(4)(5)−1
5x+20−x=4x+20−1

Combine Like Terms:

(5x−x)+(20)=(4x)+(20−1)
4x+20=4x+19
4x+20=4x+19

Subtract 4x from both sides:

4x+20−4x=4x+19−4x
20=19

Subtract 20 from both sides:

20−20=19−20
0=−1

There isn't any solutions.

6 0

2 years ago

Solve for x please refer to image

QveST [7]

Answer:

x = 40

Step-by-step explanation:

Sum of interior angle of an n-polygon = (n - 2)*180

The polygon given is pentagon with 5 sides.

Sum of the polygon = (5 - 2)*180 = 540°

Therefore, sum of all its interior angles would be:

5x + 150 + (3x - 30) + 70 + (2x - 50) = 540°

Solve for x

5x + 150 + 3x - 30 + 70 + 2x - 50 = 540

Collect like terms

5x + 3x + 2x + 150 - 30 + 70 - 59 = 540

10x + 140 = 540

10x = 540 - 140 (Subtraction property of equality)

10x = 400

x = 400/10 (division property of equality)

x = 40

6 0

2 years ago

Find the circumference of a circle whose radius is 4 feet. Use 3.14 for Pi.

slavikrds [6]

Answer:

25.12

Step-by-step explanation:

The formula of the circumference of a circle is: C = 2(pi)(r)

Plug in 3.14 for pi and 4 for the radius.

C = 2(3.14)(4)

Multiply.

C = 25.12

5 0

3 years ago

Multiply Conjugates (r+1/4)r-1/4)

Mamont248 [21]

Answer:

$\large\boxed{\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\dfrac{1}{16}}$

Step-by-step explanation:

$\text{Use}\ (a+b)(a-b)=a^2-b^2\\\\\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\left(\dfrac{1}{4}\right)^2=r^2-\dfrac{1^2}{4^2}=r^2-\dfrac{1}{16}$

8 0

3 years ago

Read 2 more answers

Find the volume of the solid of revolution generated by revolving the region bounded by y = 2x^2, y = 0, and x = 2 about the x-a

Irina18 [472]

Answer:

$128 \pi/5 units^3$

Step-by-step explanation:

The volume of the solid revolution is expressed as;

$V = \int\limits^2_0 {\pi y^2} \, dx$

Given y = 2x²

y² = (2x²)²

y² = 4x⁴

Substitute into the formula

$V = \int\limits^2_0 {4\pi x^4} \, dx\\V =4\pi \int\limits^2_0 { x^4} \, dx\\V = 4 \pi [\frac{x^5}{5} ]\\$

Substituting the limits

$V = 4 \pi ([\frac{2^5}{5}] - [\frac{0^5}{5}])\\V = 4 \pi ([\frac{32}{5}] - 0)\\V = 128 \pi/5 units^3$

Hence the volume of the solid is $128 \pi/5 units^3$

5 0

2 years ago