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3 years ago

X+y=120 5.25x+3.0y=517.2

1 answer:

4 0

I will try to solve your system of equations.
x+y=120;5.25x+3y=517.2
Step: Solvex+y=120for x:
x+y+−y=120+−y(Add -y to both sides)x=−y+120
Step: Substitute−y+120forxin5.25x+3y=517.2:
5.25x+3y=517.25.25(−y+120)+3y=517.2−2.25y+630=517.2(Simplify both sides of the equation)−2.25y+630+−630=517.2+−630(Add -630 to both sides)−2.25y=−112.8−2.25y−2.25=−112.8−2.25(Divide both sides by -2.25)y=50.133333
Step: Substitute50.133333foryinx=−y+120:
x=−y+120x=−50.133333+120x=69.866667(Simplify both sides of the equation)
Answer:
x=69.866667 and y=50.133333

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3 years ago

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2 years ago

A set of city temperatures in April are normally distributed with a mean of 19.7 degrees Celsius and a standard deviation of 2 d

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 19.7, \sigma = 2$

What percentage of average city temperatures are higher than that of Cairo?

This is 1 subtracted by the pvalue of Z when X = 21.4.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21.4 - 19.7}{2}$

$Z = 0.85$

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19.77% of average city temperatures are higher than that of Cairo

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3 years ago

ILL BRAINLIEST YOU PLEASE HELP ME

joja [24]

Answer:

82°

Step-by-step explanation:

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3 years ago