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3 years ago

X+y=120 5.25x+3.0y=517.2

1 answer:

4 0

I will try to solve your system of equations.
x+y=120;5.25x+3y=517.2
Step: Solvex+y=120for x:
x+y+−y=120+−y(Add -y to both sides)x=−y+120
Step: Substitute−y+120forxin5.25x+3y=517.2:
5.25x+3y=517.25.25(−y+120)+3y=517.2−2.25y+630=517.2(Simplify both sides of the equation)−2.25y+630+−630=517.2+−630(Add -630 to both sides)−2.25y=−112.8−2.25y−2.25=−112.8−2.25(Divide both sides by -2.25)y=50.133333
Step: Substitute50.133333foryinx=−y+120:
x=−y+120x=−50.133333+120x=69.866667(Simplify both sides of the equation)
Answer:
x=69.866667 and y=50.133333

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Can someone pls help me this is due in 4 mins

GuDViN [60]

9514 1404 393

Answer:

5450

Step-by-step explanation:

Put 9% where r is in your formula and evaluate it. Of course, you must use the decimal equivalent.

5000(1 +9%) = 5000(1.09) = 5450

The account will have 5450 in it at the end of the year.

7 0

3 years ago

The diameter of a cylindrical construction pipe is7ft. If the pipe is 36ft long, what is its volume?

Svetradugi [14.3K]

Question:

The diameter of a construction pipe is 7ft. If the pipe is 35ft long, what is the volume. (Use 3.14 for pie and round your answer to the nearest cubic foot.)

Answer: V=pir^2h V=3.14*3.5^2*35 V=1346 cu ft

Not fully sure....

But it should be right...

6 0

2 years ago

1. What is the value of the y variable in the solution to the following system of equations?

ollegr [7]

Part 1)

we have

$3x-6y=3$ ------> equation A

$7x-5y=-11$ ------> equation B

Multiply by $-7$ the equation A

$-7(3x-6y)=-7*3$

$-21x+42y=-21$ ------> equation C

Multiply by $3$ the equation B

$3*(7x-5y)=-11*3$

$21x-15y=-33$ -------> equation D

Adds equation C and equation D

$-21x+42y=-21 \\21x-15y=-33\\---------- \\ 42y-15y=-21-33\\27y=-54 \\ y=-2$

therefore

the answer Part 1) is the option A

$y=-2$

Part 2)

we have

$3x+y=6$

$y=-3x+6$ ------> equation A

$6x+2y=8$

Simplify Divide by $2$ both sides

$3x+y=4$

$y=-3x+4$ ------> equation B

the lines A and B are parallel lines, because the slope m is equal

The system has no solution

therefore

the answer Part 2) is the option D

There is no x value as there is no solution to the system.

Part 3)

we have

$4x+2y=6$ ------> equation A

$x-y=3$

$y=x-3$ ------> equation B

substitute equation B in equation A

$4x+2[x-3]=6$

$6x-6=6$

$6x=12$

$x=2$

therefore

the answer part 3) is the option D

$x=2$

Part 4)

Let

x---------> The number of one-step equations

y---------> The number of two-step equations

we know that

$x+y=1,120$

$x=1,120-y$ -------> equation A

$3x-2y=1,300$ ------> equation B

substitute equation A in equation B

$3[1,120-y]-2y=1,300$

$3,360-5y=1,300$

$5y=3,360-1,300$

$5y=2,060$

$y=412$

therefore

the answer part 4) is the option D

$y=412$

8 0

3 years ago

Read 2 more answers

Suppose f(7) = 5, f'(7) = 8, g(7) = 3, and g'(7) = 4. Find h(7) and h'(7), where h(x ) = 4f (x) + 3g(x).

dusya [7]

Answer:

h(7) = 29

h'(7) = 44

Step-by-step explanation:

If $h(x) =4f(x)+3g(x)$ , to find h(7) we can substitute the values of f(7) and g(7) and we get:

$h(7)=4f(7)+3g(7)\\h(7)=4(5)+3(3)\\h(7)=20+9\\h(7)=29$

To find the derivative, we know that the derivative of a sum of functions equals the sum of the derivatives of those functions.

This would mean that $h'(x)=4f'(x)+3g'(x)$ , we can substitute the values for f'(7) and g'(7)

$h'(7)=4f'(7)+3g'(7)\\h'(7)=4(8)+3(4)\\h'(7)=32+12\\h'(7)=44$

7 0

3 years ago

Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)

Svet_ta [14]

<h2>Answer:</h2>

$\boxed{x=1, \y=-1, \ z=2}$

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}$

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}$

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}$

Step 4: solve for z, then for y, then for x:

$\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}$

$-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}$

By substituting $y=-1 \ and \ z=2$ into the first equation, we get the $x$ . So:

$x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}$

6 0

4 years ago

Read 2 more answers