<h2><u>
Answer with explanation</u>
:</h2>
Let 
be the distance traveled by deluxe tire .
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since 
is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.
Test statistic : 
where, n= sample size
= sample mean
= Population mean
=sample standard deviation
For 
, we have
By using z-value table,
P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23) [∵P(Z≤-z)=1-P(Z≤z)]
=1-0.9871=0.0129
Decision : Since p value (0.0129) < significance level (0.05), so we reject the null hypothesis .
[We reject the null hypothesis when p-value is less than the significance level .]
Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.
Answer: 70
Step-by-step explanation:
easy
Answer:
C. I,II,III
Step-by-step explanation:
Absolute value is the distance of a number from 0 on a number line. 6 is 6 units from 0, therefore this option is correct. -6 is 5 units to the left of 0, but it is still 6 units away, therefore this option is correct. 6 is 6 units away from 0, therefore, III is correct. But 0 is 0 units away from 0, therefore this option is incorrect.
Answer:
m*p/n = percent
Step-by-step explanation:
m% of n is what percent of p?
We can use ratios
m percent
------- = ---------------
n p
Using cross products
m*p = n * percent
Divide each side by n
m*p/n = percent
