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Salsk061 [2.6K]
3 years ago
10

2. On the Budget Challenge Cash Flow Spreadsheet (CFS) (this file is downloadable on the "How to Play" page of the website), wha

t column should interest earned from her checking account be entered?
Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
The template of the Budget Challenge Cash Flow Spreadsheet has the following Column Names:
A - Date

B - Deposits

C - Bank fees

D - Apartment

E - Renters Insurance

F - Car loan

G - Car Insurance

H - School loan

I - Cable

J - Energy Bill

K - Cell phone

L - Credit Card

M - Withdrawal

N - Deposits

O - Checking Account Balance

P - Comments

Interest Earned is entered in Column B which is the Deposits column. For the reason that the interest earned will unquestionably be credited by the bank into the bank account of the holder of the account. Next, it will be added in the Deposits total in Column N. 
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3 to the -4 power simplified in fraction form
Lynna [10]

Answer:

One/eighty one

6 0
3 years ago
I am so lost, please help
skelet666 [1.2K]

Answer:

u=\frac{9}{t}-\frac{1}{2} a t

Step-by-step explanation:

Step 1: Given equation: 9=\frac{1}{2} a t^{2}+u t

To get u, by subtraction equality property subtract both sides of the equation by  \frac{1}{2} a t^{2}.

\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}  

\Rightarrow 9-\frac{1}{2} a t^{2}=u t  

Step 2: By division equality property, divide both sides of the equation by t.

\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}

$\Rightarrow \frac{9}{t}-\frac{1}{2} a t=u$  

Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$.

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$.

7 0
3 years ago
Is this the answer someone help plz
ivann1987 [24]

You're right.

Since the output has different number of jumps from one number to another.

7 0
3 years ago
Read 2 more answers
What is 28x34+3767.
Mademuasel [1]

Answer:

4719

Step-by-step explanation:

4 0
3 years ago
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Would each of them be able to be the side lengths of a triangle?
ratelena [41]
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=5                  (5²=25)

13³=144 + 25


Answer:can be side lengths of a triangle

Second triangle:
 hypotenuse=12.6    (12.6²=158.76)
leg₁=6.7                ( 6.7²=44.89)
leg₂=6.5                  (6.5²=42.25)

leg₁²+leg₂²=44.89+42.25=87.14≠158.76

Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=11                  (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13   (13²=169)
leg₁=6                ( 6²=36)
leg₂=4                  (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.
8 0
3 years ago
Read 2 more answers
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