Answer:
Step-by-step explanation:
1) The center lies on the vertical line x = -5 and the the circle is tangent to (touches in one place only) the y-axis. Thus, the radius is 5.
2) Starting with (x - h)^2 + (y - k)^2 = r^2 and comparing this to the given
(x - 4)^2 + (y + 3)^2 = 6^2
we see that h = 4, k = -3 and r = 6. The center is at (4, -3) and the radius is 6.
3) Notice that A and B have the same x-coordinate, x = 15. The center of the circle is thus (15, -2), where that -2 is the halfway point between the two given points in the vertical direction. Arbitrarily choose A(15, 4) as one point on the circle. Then the equation of this circle is
(x - 4)^2 + (y + 3)^2 = r^2 = 6^2, where the 6 is one half of the vertical distance between A(15, 4) and B(15, -8) (which is 12).
Answer:
729
Step-by-step explanation:
9x9x9 = 729 in^3
Take the derivitive
f'(x)=6x^2+2x-11
find where f'(x)=0
f'(x)=0 when x=-1.53089 or x=1.19756
we use a sign chart
test values to see where the signs are
(see attachment)
f'(-2)=(+)
f'(0)=(-)
f'(2)=(+)
max happens when sign changes from (+) to (-)
min happens when sign changes from (-) to (+)
according to the chart, max is at -1.53089 and min is at 1.19756
now evaluate the original function for x=-1.53089 and x=1.19756
f(-1.53089)=12.0078
f(1.19756)=-8.30405
max at (-1.53089,12) and min at (1.19756, -8.30405)
I may have rounded off differently, but
answer is 2nd option