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3 years ago

A circular mirror measures 24 cm in diameter.

Mathematics

1 answer:

Basile [38]3 years ago

4 0

Answer:

The perimeter or circumference of a half mirror = 37.68 cm

Step-by-step explanation:

The diameter of circular measure = 24 cm

We know that the perimeter of a circular shape is called the 'circumference', with the formula

Circumference of a circle = C = 2πr

When the mirror is cut into half, the diameter gets half as well.

Thus, the diameter of a half mirror = 24/2 = 12 cm

We know that radius = r = diameter / 2 = 12/2 = 6 cm

Thus, the perimeter of half of the mirror = C = 2πr

= 2(3.14)6

= 37.68 cm

Therefore, the perimeter or circumference of a half mirror = 37.68 cm

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What is the answer please help

hram777 [196]

Answer:

B: 22.5 degrees

Step-by-step explanation:

The interior angles of a pentagon add up to 540 degrees

(if you dont believe me you can turn a pentagon into three triangles, 3x180 = 540)

So you have four same angles say measure "x" degrees, and one final one that measures "5x" degrees, so 9x = 540, and x = 60

Unless I read the problem wrong, 60 degrees is the answer which is not an option :P

Edit: Yea I read it wrong, the final angle is 5 times the other four angles COMBINED, so that angle measures "20x" degrees.

The total would be 24x = 540, and so x = 22.5

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3 years ago

Help please i’ll give extra points : )

nalin [4]

Answer:

rub the magnets with a stronger magnet then they would be more magnetized

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3 years ago

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

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3 years ago