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timurjin [86]
3 years ago
14

How do you do this problem?

Mathematics
2 answers:
faust18 [17]3 years ago
7 0

The volume of the original cylinder is

... V = π·r²·h

For r=1 and h=1, this is

... V = π·1²·1 = π

For the new cylinder, the volume is 1.089 times that amount.

... V = 1.089π = π·1.1²·(1-k)

... 1.089/1.21 = 1-k

... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%

The appropriate choice is (B) 10.

Mademuasel [1]3 years ago
3 0

Let V,r,h be the volume, radius, and height of the original cylinder, respectively.

The new cylinder has a volume 8.9% greater than its original volume, which means the new volume is V+0.089V=1.089V. The radius was increased by 10%, so the new radius is r+0.1r=1.1r. The height was decreased by k\%, which means the new height is h-0.01kh=(1-0.01k)h.

Recall that the volume of a cylinder with radius r and height h is

V=\pi r^2h

So for the new cylinder, the volume equation is

1.089V=\pi(1.1r)^2((1-0.01k)h)

1.089V=1.21(1-0.01k)(\pi r^2h)

Now V=\pi r^2h, so we can cancel those factors and solve for k:

1.089=1.21(1-0.01k)\implies0.9=1-0.01k\implies0.01k=0.1\implies k=10

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lisabon 2012 [21]

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Step-by-step explanation:

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shutvik [7]

Given:

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\lim_{x\to 3}(x^2+8x-2)

Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

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4 0
3 years ago
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son4ous [18]

Answer:

24, 14

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