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3 years ago

Which sentence has correct capitalization?

Advanced Placement (AP)

1 answer:

viva [34]3 years ago

6 0

Answer:

Luke said he met Michael Jordan when he went to a Bulls game, but Michael Jordan was too busy to sign autographs.

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The equation of the normal line of the function f(x) = x + 2 at x = -1 is

finlep [7]

Answer:

y=-2x+1.

Explanation:

you can youce a cowculater

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3 years ago

Louis Pasteur discovered that germs cause illnesses. He invented a process called pasteurization to help kill germs in food.

disa [49]

Answer: should be decrease in food borne illnesses

Explanation:because they began to do what made it kill the germs

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3 years ago

HEYY I NEED HELP WITH AN AP CALC ASSIGNMENT ASAP

Vladimir79 [104]

CALCULATOR PART

1. The area of R + S is unsigned, meaning you want to find

$\displaystyle\int_a^b\left|f(x)-g(x)\right|\,\mathrm dx$

where $[a,b]$ is the interval between the leftmost and rightmost intersections of $f$ and $g$ .

First use your calculator to find these intersections:

$\cos x=\dfrac{x+1}3\implies x\approx-3.64,x\approx-1.86,x\approx0.889$

so that $a=-3.64$ and $b=0.889$ . Now compute the integral using your calculator:

$\displaystyle\int_a^b\left|f(x)-g(x)|\,\mathrm dx\approx1.662$

2. The volume, using the washer method, is given by the integral

$\displaystyle\pi\int_{-1.86}^{0.889}(|2-g(x)|^2-|2-f(x)|^2)\,\mathrm dx\approx12.078$

3. A circle of radius $r$ has area $\pi r^2$ ; a semicircle with the same radius thus has area $\frac{\pi r^2}2$ . Each cross section of this solid is a semicircle whose diameter is the vertical distance between $f(x)$ and $g(x)$ , or $|f(x)-g(x)|$ . In terms of the diameter $d=2r$ , the area of each semicircle would be $\frac{\pi d^2}8$ . Then the volume of the solid is

$\displaystyle\frac\pi8\int_{-3.64}^{-1.86}|f(x)-g(x)|^2\,\mathrm dx\approx0.0425$

NON-CALCULATOR PART

4. The mean value theorem says that for a function $F$ continuous on an interval $[a,b]$ and differentiable on $(a,b)$ , there is some $c\in(a,b)$ such that

$F'(c)=\dfrac{F(b)-F(a)}{b-a}$

If this $F$ happens to be an antiderivative of $f$ , then we end up with

$f(c)=\displaystyle\frac1{b-a}\int_a^bf(x)\,\mathrm dx$

$\cos x$ is continuous and differentiable everywhere, so the MVT applies. We have $F'(x)=f(x)=\cos x$ , so the MVT tells us there is some $c\in[0,\pi$ such that

$\cos c=\dfrac{\sin\pi-\sin0}{\pi-0}=0$

That is, the average value of $f(x)$ on $[0,\pi]$ is 0. The MVT says there is some $c$ in the interval such that the function takes on the average value itself; this happens for $c=\frac\pi2$ .

5. This question seems to be incomplete...

5 0

4 years ago

In the article “Who Shaped our Behaviors? Peers or Parents?”, Judy Rich Harris suggests that __________ are the most influential

Andrei [34K]

Answer:

C. Peers

Explanation:

Edg 21

6 0

3 years ago

Read 2 more answers

Which of the following statements is true?

Elis [28]

I believe that the answer Is all of the above.
We should all know that gravity keeps the planets in orbit. Also, electrons can leave an atom if they have enough energy.
I hope this helps!

4 0

2 years ago

Read 2 more answers