Answer:
1/ab en (c/be^-x+c)
Step-by-step explanation:
Sure is a harsh question! Here's my Explanation
b+ce^x = t
ce^x an = dt
e^xan = dt/c
an = dt/ce^x = dt/c(t-b/c) = at/(t-b)
en = t-b/c
A/b+ce^x dx = a/t dt/t-b
a ∫1/t (t-b) dt = 1/a∫ (1/(t-b) - 1/t) dt
= 1/ab [∫1/(t-b) dt + ∫-1/t dt]
= 1/ab [en (t-b) - en(t)]
= 1/ab en ((t-b)/t)
t = b + ce^x
= 1/ab en (b+ce^x -b/b+ce^x)
=1/ab en (ce^x/b+ce^x)
= 1/ab en (c/be^-x+c)
Answer:
30+31+32 =93. Smallest is 30
Answer: ![405.7\ ft](https://tex.z-dn.net/?f=405.7%5C%20ft)
Step-by-step explanation:
Given
After 11 sec, diver is 69 feet below sea level
after 28 s , it is 195 feet
rate of traveling
![\Rightarrow u=\dfrac{195-69}{28}\\\\\Rightarrow u=4.53\ ft/s](https://tex.z-dn.net/?f=%5CRightarrow%20u%3D%5Cdfrac%7B195-69%7D%7B28%7D%5C%5C%5C%5C%5CRightarrow%20u%3D4.53%5C%20ft%2Fs)
after 1.5 minutes, that is 90 s, diver must have traveled
Two consecutive integers are -4-9 and 1(-13)
Yes because you are multiplying 3 z’s and also 3z’s