Answer:
To determine the fraction for the inheritance of Red green colorblindness the genotype of their parents must be considered although neither John nor Ann is color blind there is a very high probability that Ann will be a carrier if that is the case the fractions of the daughters of John and Ann that are expected to be carriers of that trait is 50% chance.
Explanation:
A punnet square can be used to determine any possible genotypic combinations in the parents. color blindness is a recessive X-linked trait in which the patient is not able to distinguish, red or green or blue color. The normal gene and its recessive allele are carried by X chromosome in men, this color blindness appears in the presence of a single recessive gene Whereas in women color blindness occur only when both chromosome carry the gene this shows criss cross inheritance
Answer: Nematoda
Explanation: The Dracunculus medinensis is a parasite that is often referred to as a roundworm. The answer Nematoda is correct because is is the phylum that classifies roundworms and is greek for "roundworms"
Answer:
As a cell grows in size, the surface area gets bigger, but the volume gets bigger faster. Thinking about this as a ratio (division), the volume is the denominator and the surface area is the numerator. If the volume is getting very big, then the ratio itself will be getting very small.
Answer:
a. all purple flowers in the F1 generation.
Explanation:
According to the given information, the allele for purple flower color (lets assume P) is dominant over while the allele of flower color (p). When two pure breeding purple (PP) and white flowered (pp) plants are crossed, the F1 would have all "purple flowered progeny with genotype Pp".
According to the Mendel's law of dominance, the hybrid genotype exhibits the dominant phenotype. Here, the allele "P" is dominant over allele "p". Hence, the genotype "Pp" would exhibit purple flower color and all the F1 progeny would have purple flowers.
