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Assoli18 [71]
3 years ago
5

Write an equation for g(x), a translation of f(x) 4 units to the right and 3 units down.

Mathematics
1 answer:
Hoochie [10]3 years ago
3 0
I’m pretty sure it’s c) I’m sorry if it’s wrong :)
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I need math help please
poizon [28]

Answer:

n+11=15

  -11 -11

n=4

Step-by-step explanation:

subtract 11 from both sides

5 0
4 years ago
Read 2 more answers
What is the slope for -4x-3y=6
loris [4]

Answer: y=4/3x+2


Step-by-step explanation:

-4x-3y=6

+4x       +4x

-3y=4x+6

-3/-3=4/3+6/3

y=4/3x+2


7 0
3 years ago
ASAP Free points, please solve -2m+36=2(6m-3)?<br>​
Komok [63]

Answer:

m = 3

Step-by-step explanation:

We can try and isolate m on one side of the equation by following the rules of simplifying equations.

-2m + 36 = 2(6m - 3)\\\\-2m+36 = 12m - 6\\\\36 = 14m-6\\\\42 = 14m\\\\3 = m

Hope this helped!

6 0
3 years ago
Read 2 more answers
About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number
olganol [36]

Answer:

1) E(X) = np = 120*0.1 =12

SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

2) P(X\geq 16)

And we can use the normal approximation given by:

X \sim N(12, \sigma =3.286)

And we can use the z score formula given by:

z = \frac{X -\mu}{\sigma}

And if we find the z score for 16 we got:

z = \frac{16-12}{3.286}= 1.217

And we can find this probability using the normal standard distribution or excel and we got:

P(Z>1.217) = 0.112

3) For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

X\sim Binom(n= 120 , p =0.1)

Part 1

The mean is given by:

E(X) = np = 120*0.1 =12

And the deviation would be:

SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

P(X\geq 16)

And we can use the normal approximation given by:

X \sim N(12, \sigma =3.286)

And we can use the z score formula given by:

z = \frac{X -\mu}{\sigma}

And if we find the z score for 16 we got:

z = \frac{16-12}{3.286}= 1.217

And we can find this probability using the normal standard distribution or excel and we got:

P(Z>1.217) = 0.112

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

7 0
3 years ago
According to these measure, is it possible that the heaviest piece of fruit in the two samples was an orange? Explain why or why
nalin [4]

Answer:

The measures given which are median and interquartile range have no effect on what the maximum value of a certain distribution will be.

In essence, the information given about the samples of fruits and apples do not point to which fruit sample should possess the sample with maximum weight as the information only gives a general description of each distribution. This means that either samples of orange or apple could have the heaviest piece of fruit.

Step-by-step explanation:

Pls brainliest?

5 0
3 years ago
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