I hope this can help you.
Given:
radius = 18mm
height = 6mm
pi = 3.14
volume of a cone is computed by multiplying pi, radius raised to the 2nd power, and height, which has been divided by 3.
v = πr²h/3
v = 3.14 * (18mm)² x 6mm/3
v = 3.14 * 324mm² x 2mm
v = 2034.72 mm³
<span>volume rounded to the nearest tenth would be 2034.70 mm³</span>
Wow that is hardddddddddddddddddddddddddddddddddddddddd
Answer is •D because of the seburation
Answer:
x = π/2 + nπ or x = (2/3 π + 2nπ) or x = (4/3 π + 2nπ)
Step-by-step explanation:
1 + cosx + cos2x=0
1+cosx+(2cos²x -1) = cosx + 2cos²x = cosx (1 + 2cosx) = 0
cosx = 0
x = 90° (π/2) or (90+180) or (90+180x2) .... i.e π/2 + nπ
or 1 + 2cosx = 0
cosx = -1/2
x = 120° or 240° (2/3 π or 4/3 π) or (120 + 360 : 2/3 π + 2π) (120 + 2 * 360)
.... i.e. (2/3 π + 2nπ)
or (240 + 360 : 4/3 π + 2π) (240 + 2 * 360) .... i.e. (4/3 π + 2nπ)
