Answer:
A. x = 3/k.
Step-by-step explanation:
5kx + 6 = 7kx
5kx - 5kx + 6 = 7kx - 5kx
6 = 2kx
x = 6 / 2k
x = 3/k.
Answer:
a. 0.0000009 m
b. 6,130, 000, 000
c. 100,000 light years
d. 0.00001 mm
e. 0.0000010 kg
Step-by-step explanation:
Here, we want to come from the standard form to the decimal form
In doing this, we consider the power of 10 attached
If negative, we count leftwards, if positive, we count right-wards
The number of times we count is the power of 10 attached. The count means we are moving the decimal point
For numbers with out visible decimal point, it is at the back of the most right-ward number
Thus, we have these as;
a. 9 * 10^-7
= 0.0000009 m
b. 6.130 * 10^9
= 6,130, 000, 000
c. 1 * 10^5
= 100,000 light years
d. 1 * 10^-5 mm
= 0.00001 mm
e. 10^-7
= 0.0000010 kg
<h2>
Answer:</h2>
cos 28°cos 62°– sin 28°sin 62° = 0
<h2>
Step-by-step explanation:</h2>
From one of the trigonometric identities stated as follows;
<em>cos(A+B) = cosAcosB - sinAsinB -----------------(i)</em>
We can apply such identity to solve the given expression.
<em>Given:</em>
cos 28°cos 62°– sin 28°sin 62°
<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>
A = 28°
B = 62°
<em>∴ Substitute these values into equation (i) to have;</em>
<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>
<em />
<em>Solve the left hand side.</em>
<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>
⇒ 0 = <em>cos28°cos62° - sin28°sin62° (since cos 90° = 0)</em>
<em />
<em>Therefore, </em>
<em>cos28°cos62° - sin28°sin62° = 0</em>
<em />
<em />
