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olchik [2.2K]
3 years ago
12

I need help ASAP please help me

Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

your question is sideways take the picture again plz.

Step-by-step explanation:

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Anyone know the answer to this? If so please help?
Elina [12.6K]

Answer:

2nd and 5th

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
jake ordered 275 large pizzas for a party. when the party was over he had 250 large pizzas remaining. estimate the percent decre
Oksana_A [137]
20 % I think so maybe
6 0
3 years ago
Read 2 more answers
I will give 5 points
ikadub [295]

Use the sum of cubes factoring rule

a^3 + b^3 = (a+b)(a^2 - ab + b^2)

to transform the left hand side into the right hand side.

\frac { \sin^{3} \theta + \cos^{3} \theta } { \sin \theta + \cos \theta } = 1 - \sin \theta \cdot \cos \theta\\\\\frac { (\sin \theta + \cos \theta)(\sin^2 \theta - \sin \theta \cdot \cos\theta + \cos^2 \theta) } { \sin \theta + \cos \theta } = 1 - \sin \theta \cdot \cos \theta\\\\

\sin^2 \theta - \sin \theta \cdot \cos\theta + \cos^2 \theta = 1 - \sin \theta \cdot \cos \theta\\\\(\sin^2 \theta + \cos^2\theta)- \sin \theta \cdot \cos\theta = 1 - \sin \theta \cdot \cos \theta\\\\1- \sin \theta \cdot \cos\theta = 1 - \sin \theta \cdot \cos \theta \ \ \checkmark\\\\

Throughout the entire process, the right hand side stayed the same.

On the last step, I used the pythagorean identity.

8 0
2 years ago
Write the equation of the line that passes through (-1,8) and is parallel to the graph of y = 4x - 2
NikAS [45]

Answer:

When a line is parallel to another line, they have the same slope. So far the equation would be, y=4x+b. To find the value of b, substitute the given point into the equation.

8=4(-1)+b

8=-4+b

b=12

So, the equation of the line is y=4x+12.

:)

8 0
2 years ago
Use the quotient of negative numbers:
strojnjashka [21]
If you divide negative by positive it will be negative.
If you divide positive by negative it will be negative.
If you divide 2 negatives you get a positive.
I hope this helps :)
4 0
4 years ago
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