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valentinak56 [21]
3 years ago
9

A pancake recipe calls for 4 cups of flour and 3 cups of milk.Does a recipe calling for 2 cup of flour and 1.5 cups milk use the

same ratio of flour to milk?
Mathematics
2 answers:
kolbaska11 [484]3 years ago
5 0
Yes, because if you divide 4 and 3 by 2, you get 2 and 1.5
Marina CMI [18]3 years ago
5 0

Hi there!

In order for the ratio to be the same, the transformations between the initial pancake recipe and the second recipe need to be the same from flour to flour and from milk to milk.

4 cups of flour was divided by 2 in order to become 2 cups of flour in the second recipe.

3 cups of milk was divided by 2 in order to become 1.5 cups of milk in the second recipe.


Since both milk and flour mesures went throug the same transformation (divided by 2) from recipe one to recipe two, you can then say that the ration is the same.


There you go! I really hope this helped, if there's anything just let me know! :)

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3) 14 pennies to 35 pennies​
Leno4ka [110]

Answer:

<h2>2/5</h2>

Step-by-step explanation:

14/35

Find the GCD of numerator and denominator

GCD of 14 and 35 is 7

Divide both the numerator and denominator by the GCD

14 ÷ 7

35 ÷ 7

2/5

I'm always happy to help :)

5 0
3 years ago
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
3 years ago
What is the answer for -8(w-6=32
vladimir2022 [97]
The answer would be 2 because the problem(after rewriting it) is -8w+48=32. so then you subtract 48 from both sides and get -8w=-16. then divide both sides by -8 and you get 2
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xenn [34]

Answer:

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3 years ago
PLZ HELP ITS DUE T MIDNIGHT
kkurt [141]
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