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scoray [572]
3 years ago
5

Tanθ= a. 1 - cot^2 θ b. 1/cot θ c. 1 + sec^2 θ

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0

Answer:

tanθ =  \frac{sinθ}{cosθ} \\ =  \frac{1}{ \frac{cosθ}{sinθ} }  \\  =  \frac{1}{cotθ}

<u>b. 1/cot θ</u>

erma4kov [3.2K]3 years ago
5 0

Answer:

tanθ =  \frac{sinθ}{cosθ} \\ =  \frac{1}{ \frac{cosθ}{sinθ} }  \\  =  \frac{1}{cotθ}

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