3 years ago

Tanθ= a. 1 - cot^2 θ b. 1/cot θ c. 1 + sec^2 θ

Mathematics

2 answers:

DIA [1.3K]3 years ago

7 0

Answer:

$tanθ = \frac{sinθ}{cosθ} \\ = \frac{1}{ \frac{cosθ}{sinθ} } \\ = \frac{1}{cotθ}$

<u>b. 1/cot θ</u>

erma4kov [3.2K]3 years ago

5 0

Answer:

$tanθ = \frac{sinθ}{cosθ} \\ = \frac{1}{ \frac{cosθ}{sinθ} } \\ = \frac{1}{cotθ}$

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