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Gwar [14]
2 years ago
6

IR = V (solve for R) *

Mathematics
1 answer:
VashaNatasha [74]2 years ago
6 0

Answer:

R = \frac{V}{I}

Step-by-step explanation:

IR = V ( isolate R by dividing both sides by I )

R = \frac{V}{I}

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True or false? In a two-column proof, the left column contains a series of deductions. A. True B. False
Eddi Din [679]

Answer:

A. True

Step-by-step explanation:

4 0
4 years ago
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Which expression is equivalent to 5 x + 10 y minus 15?
BlackZzzverrR [31]

Answer:

C

Step-by-step explanation

5*x=5x -----5*2=10------5*3=15

7 0
4 years ago
Last homework for mathematics, mr Thompson!
Flura [38]

Answers:

  1. Have a common difference
  2. Have a common factor
  3. Have a linear first difference

============================================================

Explanation:

Linear functions, such as y = 2x+5, have a common difference. In that example, the common difference would be 2 since we add 2 to each term to get the next one. Consider when x = 1 and that leads to y = 7. Then when x = 2, we have y = 9. Then when x = 3, we have y = 11, and so on. The sequence of y values {7,9,11,...} shows we add 2 each time.

------------------

Exponential functions have us multiply the previous term by some common factor to get the next term. A sequence like {2,6,18,...} has us multiply by 3 each time and the exponential function modeling this sequence is y = 2(3)^(x-1) where x is a natural number. So this is an example showing that exponential functions have a common factor, or we can call this a common ratio.

------------------

Quadratic functions are a bit strange.

Let's consider the quadratic of y = x^2. The sequence of y values it generates is {1,4,9,16,25...} for positive integers x = 1, 2, 3, 4, 5....

Let's subtract the adjacent terms (larger - smaller)

  • 4-1 = 3
  • 9-4 = 5
  • 16-9 = 7
  • 25-16 = 9

Note the results of 3,5,7,9 are in a linear sequence (we're adding 2 to each increment value, so the next increment would be +11). We can consider this a linear first difference.

------------------

For any of these functions, I'm restricting x to be an integer and x = 1 is the smallest input possible.

6 0
3 years ago
How to solve this problem
Eddi Din [679]

Answer:

Solving the radical \pm\sqrt{-81}  we get \mathbf{\pm9 \ i}

Step-by-step explanation:

We need to express the radical \pm\sqrt{-81} using the imaginary unit i

Prime factors of 81 are: 3x3x3x3

and \sqrt{-1}=i

Solving:

\pm\sqrt{-81}\\=\pm\sqrt{81}\sqrt{-1}\\=\pm\sqrt{3\times3\times3\times3}i\\ =\pm\sqrt{3^2\times3^2}i\\=\pm3\times3\ i\\=\pm9 \ i

So, Solving the radical \pm\sqrt{-81}  we get \mathbf{\pm9 \ i}

8 0
3 years ago
PLEASE HELP !! WILL MARK THE BRAINLIEST <br><br> Solve the system y = -x + 7 and y = 0.5(x - 3)2
Leno4ka [110]
Y = -X + 7
Y = .5(X-3)2

Alright check it out. Substitute the Y in the second equation for the first equation so...

-X + 7 = .5(X-3)2

After this, you have to get rid of the .5 and the 2 which is easy peasy because they just cancel out. If you were to multiply by half and then multiply by 2 then you'd be back to where you started. So...

-X + 7 = X - 3

Move the X to combine them on one side, I moved the -X to the opposite side by adding X to each side so you get...

7 = 2X - 3

You then add 3 to both side so...

10 = 2X

Divide by 2

X = 5

So...

Y = -5 + 7
Y = 2

Y = .5(5-3)2
Cancel out the .5 and the 2
Y = 5-3
Y = 2

(5,2) is your answer
6 0
3 years ago
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