All categories

3 years ago

PLEEAAASE HELPPPPPDistance = ________ x timeA. flowB. rateC. work

Mathematics

2 answers:

scZoUnD [109]3 years ago

8 0

Answer:

B:rate

Step-by-step explanation:

the formula distance= rate × time

a_sh-v [17]3 years ago

4 0

Answer:

Step-by-step explanation:

The formula for distance is rate × time.

Flow and work don't make sense. Also, work is force × distance.

However, you were given rate is equal to distance/time (r=d/t) and were asked to find what distance would be:

in that case, we'll isolate d onto one side

here's the equation

r=d/t

multiply by t on both sides

rt=d, or rate × time equals distance

either way it's B

Hope this helps!

You might be interested in

What are expressions for MN and LN? Hint Construct the altitude from M to LN.

Nikitich [7]

The question is missing the figure. So, it is in the atachment.

Answer: MN = x $\sqrt{2}$ LN = $\frac{x}{2}.(\sqrt{2} + \sqrt{6} )$

Step-by-step explanation: The first figure in the attachment is the figure of the question. The second figure is a way to respond this question by tracing the altitude from M to LN as suggested. When an altitude is drawn, it forms a 90° angle with the base, as shown in the drawing. To determine the other angle, you have to remember that all internal angles of a triangle sums up to 180°.

For the triangle on the left of the altitude:

45+90+angle=180

angle = 45

For the triangle on the right:

30+90+angle=180

angle = 60

With the angles, use the Law of Sines, which is relates sides and angles, as follows:

$\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}$

For MN:

$\frac{x}{sin(30)} = \frac{MN}{sin(45)}$

MN = $\frac{x.sen(45)}{sen(30)}$

MN = x $\sqrt{2}$

For LN:

$\frac{LN}{sen(105)} =\frac{x}{sin(30)}$

LN = $\frac{x.sin(105)}{sin(30)}$

We can determine sin (105) as:

sin(105) = sin(45+60)

sin(105) = sin(45)cos(60) + cos(45)sin(60)

sin(105) = $\frac{\sqrt{2} }{2}.\frac{1}{2} + \frac{\sqrt{2} }{2}.\frac{\sqrt{3} }{2}$

sin(105) = $\frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}$

LN = $\frac{x.sin(105)}{sin(30)}$

LN = $x.(\frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4} ) .2$

LN = $\frac{x}{2}.(\sqrt{2} + \sqrt{6} )$

The expressions for:

MN = x $\sqrt{2}$

LN = $\frac{x}{2}.(\sqrt{2} + \sqrt{6} )$

6 0

3 years ago

Can retainers still fit w a small gap?

natali 33 [55]

Answer:

Retainers have been designed to be used as an end of treatment to help retain your teeth in their new position. ... These are removable and fixed retainers. The reason why retainers can't be used to close a gap is because they are fitted at the end of treatment and are made to fit the straight teeth mould.

hope it help u

itz by Riddhi

7 0

3 years ago

Read 2 more answers

Volume and surface area really don’t understand this could someone help?

astra-53 [7]

Answer:

Step-by-step explanation:

1:A=b times h as its a parallelogram:21 times 33= 63

2:A=a+b /2 h as its a trapezium= 91

3:A=πr squared=26.42

4:A=hb/2=27 times 6/2=216

3 0

4 years ago

Tom Worker pays $900 annually for $60,000 worth of life insurance.

Amanda [17]

Answer: 1) $9000

2) $5340

3)59.3%

Step-by-step explanation:

Since we have given that

Worth of life insurance = $60000

Amount of premium = $900

After the end of 10 years,

1) Amount of premium Tom had paid is given by

$10\times 900=\$9000$

2) At the end of 10 years ,

The cash value of his policy by using the table is given by

$\frac{89}{1000}\times 60000\\\\=\$5340$

3) At the end of 10 years ,

Ratio of cash value to premiums paid be

$5340:9000\\\\=\frac{5340}{9000}\times 100\\\\=59.3\%$

7 0

3 years ago

-4m + 2n = 6 -4m + n = 8 solve for and x and y steps

hammer [34]

I am doing this problem assuming that you mean to solve for m and n as x and y do not exist in this system of equations.

-4m+2n=6

-4m+n=8

We can see that the coefficient of x for both equations are -4; therefore, elimination with subtraction is possible.

First equation - second equation

n=-2

Then substitude back in to solve for m

-4m+(-2)=8

4m=10

m=5/2

Therefore the answer is

n= - 2

m= 5/2

I hope this helped and if you have any questions please ask.

5 0

3 years ago

PLEEAAASE HELPPPPPDistance = ________ x timeA. flowB. rateC. work​

PLEEAAASE HELPPPPPDistance = ________ x timeA. flowB. rateC. work