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3 years ago

Triangle DEF is a scaled copy of triangle ABC. Which angle in the scaled copy corresponds to angle C?

Mathematics

2 answers:

Alexxx [7]3 years ago

3 0

Its F! F is corresponds to the angel C!

damaskus [11]3 years ago

3 0

F. You can tell by ratio of side lengths, which is 1.5, which means that one side of triangle DEF is 1.5 times longer than the corresponding side in triangle ABC. We know that line AC corresponds to line DF because 9 is 1.5 times larger than 6. We also know that corresponding side lengths have corresponding angle measures, so we know that angle C corresponds to angle F.

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X+5/2 + x−3/3 =3 1/6

Nataly [62]

The answer is x=-1/2

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3 years ago

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(3)/(4)x-3=(2)/(5) write this without fractions

Juliette [100K]

4 -5 =0

4 5

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3 years ago

Which rectangular prism will have the largest volume?

djverab [1.8K]

Answer:

The rectangular prism with these dimensions w = 3 cm, l = 5 cm, h = 5 cm has the largest volume.

Step-by-step explanation:

The formula for the Volume of a V = 3 * 5 * 5

V = l * w * h

V = 3 * 5 * 5

V = 75 cm³

The rectangular prism with these dimensions w = 3 cm, l = 5 cm, h = 5 cm has the largest volume.

5 0

3 years ago

Fill in the missing equation

Valentin [98]

Start with y=mx+b

B is your y intercept
m is your slope

The points you have are (-1,4) and (1,-2)
To find the slow you Do Y2-Y1/X2-X1
(-2-4)/ (-1-1)
-6/-2
your m is 3

Now you go back to the equation of a Line y=mx+b
to find b (your y intercept) take on of the two points, and substitute it's y value in the equation Let's take (1,-2)

Y=mx+b
-2=3(1)+b
-2=3+b
b=-5

you now know that
b=-5
m=3x

The equation is
y=3x-5

7 0

3 years ago

Suppose that the lifetime of tv tubes are normally distributed with a standard deviation of 1.1 years. Suppose that exactly 20%

IrinaK [193]

Answer:

4.924 years

Step-by-step explanation:

Lets denote X the lifetime of a tv tube (In years). X has distribution $N(\mu, 1.1)$ , with $\mu$ unknown.

We know that P(X < 4) = 0.2. Using this data, we can find the value of $\mu$ throught standarization.

Lets call $Z = \frac{X - \mu}{1.1}$ the standarization of X. Z has distribution N(0,1), and its cummulative function, $\phi$ is tabulated. The values of $\phi$ can be found in the attached file.

$P(X < 4) = P(\frac{X - \mu}{1.1} < \frac{4 - \mu}{1.1}) = P(Z < \frac{4 - \mu}{1.1}) = \phi(\frac{4 - \mu}{1.1}) = 0.2$

The value q such that $\phi (q) = 0.2$ doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that $\phi(-q) = 0.8$ , hence -q must be equal to 0.84. Thus, q = -0.84