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vodomira [7]
3 years ago
15

What is the domain of the given function?

Mathematics
2 answers:
Vaselesa [24]3 years ago
7 0

Answer: i think it is A pls correct me if i'm wrong :)

Step-by-step explanation:

Zanzabum3 years ago
7 0
A 0,1,2,3 would be the domain
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Find the smallest number should be subtracted from 9340 so as to get a perfect square.
nikdorinn [45]

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nearby number = 96

square of 96 = 9216

9340- 9216= 124

the smallest number 124 should be subtracted from 9340 so as to get a perfect square.

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A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a
UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

P_{t}=P_{0}+500t

Where P_{t} = Population after t years

P_{0}= Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = \frac{5000}{500}

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = \frac{15000}{500}

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = \frac{35000}{500}

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

T_{n}=T_{0}(1+\frac{r}{100})^{t}

T_{n} = Population after t years

T_{0} = Initial population

t = time in years

For double once,

Population after t years = 10000

10000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{10000}{5000}

(1.05)^{t}=2

Take log on both the sides

log(1.05)^{t}=log2

tlog(1.05) = log2

t = \frac{log2}{log1.05}

t = 14.20 years

For double twice,

Population after t years = 20000

20000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{20000}{5000}

(1.05)^{t}=4

Take log on both the sides

log(1.05)^{t}=log4

tlog(1.05) = log4

t = \frac{log4}{log1.05}

t = 28.413 years

For double thrice

Population after t years = 40000

40000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{40000}{5000}

(1.05)^{t}=8

Take log on both the sides

log(1.05)^{t}=log8

tlog(1.05) = log8

t = \frac{log8}{log1.05}

t = 42.620 years

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3 years ago
Solve 8 and 9 and show work
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Looking at D:  If you subtract 8 from both sides of this inequality, you obtain 

x<-11, which is the correct answer.
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There is triangle ABC triangle XYZ is similar to ABC scale factor 1/4
Agata [3.3K]

Answer:

The side that is labeled as 7 is 28 the side that is labeled as 5 shoud be 20 the side that is labeled as 4 should be 16

Step-by-step explanation:

Sorry I cant take a screen shot with my computer but here is the explanation it says that the scale factor is 1/4 so I just did 1/4  ÷  7,5,and 4

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3 years ago
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