First subtract 2 revolutions from the - 840 :- (- (840-720) = -120
This gives sin -120 which is in the 3rd quadrant of the unit circle
sin -120 = - sin 60 = - sqrt3/2
Slope of the given line = 4
slope of the req. line = 4
equation of the line
y - y1 = m(x - x1)
y + 8 = 4(x - 3)
y + 8 = 4x - 12
4x - y - 12 - 8 = 0
4x - y - 20 = 0
Answer:
No 2
Step-by-step explanation:
1&15 and 3&5 are factors of 15
