The given box has the shape of a <u>cuboid</u>, since its <em>height</em> is greater than its <em>width</em>. Thus, the <em>maximum volume</em> for such box is 11200
.
The <u>volume</u> of an object is a measure of it <em>containing</em> capacity. Since the given box has a taller <em>height</em> than its <em>width</em>, then it has the shape of a <em>cuboid</em>. The<u> volume</u> of a cuboid is given as:
volume = length x width x height
= area x height
Given that the <u>sum</u> of the <em>perimeter</em> of its base and its <em>height</em> is not more than 108 inches, we can say; let the sides of the <em>square</em> base be represented by l and its height by h.
Then;
4l + h = 108
Therefore, maximum volume for the box can be attained when l = 20 inches and h = 28 inches.
So that;
4(20) + 28 = 80 + 28
= 108 inches
Thus;
maximum volume = area of the square base x height
= 400 x 28
maximum volume = 11200 
The <u>maximum</u> <u>volume</u> for such a box would be 11200
.
Visit: brainly.com/question/20463446
Answer:
112.249
I added more places after the decimal in case you need to round it.
The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula:

Were

is the area in square kilometers

is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so

. Lets replace that value in our formula to find

:

Now, to find the population density of the filed, we are going to use the population density formula:

where

is the population density in <span>in burrows per square kilometer
</span>

is the number of burrows

is the are of the field
We know that

and

, so lets replace those values in our formula:


We can conclude that the <span>density of prairie dog burrows is approximately
2444 burrws per square kilometer.</span>