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slavikrds [6]
2 years ago
10

. A perpendicular from the origin meets a line at (4, -5), find the equation of the (a) perpendicular (b) line​

Mathematics
1 answer:
kirill [66]2 years ago
5 0

Answer:

y = ⅘x - 41/5

Step-by-step explanation:

slope of the line from the origin = -5/4

slope of any perpendicular to the line = ⅘

equation of the line from the origin:

y = -(5/4)x

perpendicular to the line that passes through (4,-5):

y+5 = ⅘(x-4)

y = ⅘x - 41/5

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Answer:

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Step-by-step explanation:

To answer a question like this, it is often helpful to graph the function or to rewrite it to vertex form.

  f(x) = 3x^2 +6x -8

  f(x) = 3(x^2 +2x) -8 . . . . factor the leading coefficient from x terms

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The form of this equation tells you that the graph is a parabola that opens upward. Its vertex is (-1, -11), so the minimum value is -11. The range is the vertical extent of the function values, so goes upward from -11:

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* Vertex form is ...

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The square is completed by adding the square of half the x-coefficient inside parentheses, and subtracting the equivalent amount outside parentheses. Here, we had 2x inside parentheses, so we added (2/2)^2 = 1 inside and -3(1) outside, because "a" was 3.

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Brainly provides tools for properly rendering math symbols. 2-11 is not the same as ≥-11.

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