Answer: 152ft^2
The amount of material needed to construct the tent is 152ft^2
Step-by-step explanation:
The amount of material needed to construct a triangular tent= the surface area of the triangular tent.
S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.
S.A = Ab + At + Ar ....1
Area of the base Ab= Length × width = 8×6 = 48ft^2
Area of the two triangles At = 2 × 0.5 × width × height
At = width × height = 6×4 = 24ft^2
Area of the two rectangles Ar = 2 × side measurement × length
Side measurement is given as 5ft.
or it can be calculated using;
Side length can be calculated using Pythagoras theorem.
Examining the figure attached, we can see that;
Side breadth b = √(h^2 + (w/2)^2)
b = √(4^2 + (6/2)^2) = √(16+9) = √25
b = 5ft
Ar = 2×5×8 = 80ft^2
From eqn1, S.A can be solved as;
S.A = 48 + 24 + 80
S.A = 152ft^2
Answer:
The answer is b = 8a
Step-by-step explanation:
As, 0 x 8 = 0
2 1/2 = 5/2, 5/2 x 8 = 20
5 x 8 = 40
7 1/2 = 15/2, 15/2 x 8 = 60
10 x 8 = 80
13 1/2 = 27/2, 27/2 x 8 = 108
So all variables "a" when multiplied by 8 will give us the value in "b"
So b = 8a
13)
Circumference (C) = 2π·r
11π = 2π·r
11/2 = r
******************************
Area (A) = π·r²
= π·(11/2)²
= 121π/4
≈ 94.985 in²
14)
diameter = 2r
42 = 2r
21 = r
*******************
Area (A) = π·r²
= π·(21)²
= 441π
≈ 1384.74 in²
***************************
$280/1384.74 in²
x = $0.20
Answer: about 20 cents per square inch
I tried to make a list and found 27 ways
tell me if I missed any
order is
(3point,2point,1point)
(0,0,15)
(0,1,13)
(0,2,11)
(0,3,9)
(0,4,7)
(0,5,5)
(0,6,3)
(0,7,1)
(1,0,12)
(1,1,10)
(1,2,8)
(1,3,6)
(1,4,4)
(1,5,2)
(1,6,0)
(2,0,9)
(2,1,7)
(2,2,5)
(2,3,3)
(2,4,1)
(3,0,6)
(3,1,4)
(3,2,2)
(3,3,0)
(4,0,3)
(4,1,1)
(5,0,0)
27 is my answer
