Answer:
No solutions
Explanation:
The given system of equations is
2y = x + 9
3x - 6y = -15
To solve the system, we first need to solve the first equation for x, so
2y = x + 9
2y - 9 = x + 9 - 9
2y - 9 = x
Then, replace x = 2y - 9 on the second equation
3x - 6y = -15
3(2y - 9) - 6y = -15
3(2y) + 3(-9) - 6y = -15
6y - 27 - 6y = -15
-27 = -15
Since -27 is not equal to -15, we get that this system of equation doesn't have solutions.
6m+30 is the answer.
Multiply 6 and m and you get 6m.
Multiply 6 and 6 and you get 30.
6m+30
We are given with two equations bearing a square root sign within. In this case, the goal of f(x) is to have a value of x not greater than 1 and not less than -1. g(x) should have x only equal to positive numbers. Hence the domain for (f+g) is equal to the positive numbers greater than or equal to 1.in 2. we multiply both functions to give sqrt of x*(1-x2). the domain should be also positive numbers greater than or equal to 1.
Answer:
any of them work
Step-by-step explanation:
2/3x-40=5/6(x+36)
multiply each side by 6 to get rid of the fraction
6* 2/3x- 6*40=6*5/6(x+36)
4x -240 = 5(x+36)
distribute
4x-240 = 5x +180
subtract 4x from each side
-240 = x +180
subtract 180 from each side
-420 =x
