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Nata [24]
2 years ago
15

What is the range of the function graphed below? ​

Mathematics
1 answer:
lord [1]2 years ago
7 0

Answer:

__________-3<Y<4______________

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What is the value of x in the figure below?
Mrac [35]

Answer:

x = 125°

Step-by-step explanation:

180° - 55° = 125°

125°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0
3 years ago
What is the value of 452 tens?
Law Incorporation [45]
The anwser is 4,520. :D
6 0
3 years ago
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5. The graph of a proportional relationship contains the point with coordinates (3,12).
Dmitriy789 [7]
Give me brainly and ill tell u
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2 years ago
Which table of values represents the equation y = 1/2x?​
gtnhenbr [62]

Answer:

The third option choice

Step-by-step explanation:

In the equation all your doing is halfing the x to get y

Or multiplying it by . 5

So half of what your x is is what your y is

4 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
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