Since there are no multiples other than 1 and -1 that could multiply in any way to equal 1, those are the only numbers you can really work with
it is a possibility that a, b, and c could equal 1 but then it would go wrong when comes time to subtract since all numbers are equal and cannot subtract largest from smallest.
a logical approach would be to try -1, -1, and 1 since -1 * -1 = 1 and then 1* 1 =1
we can make a= -1 , b= -1, and c= 1
(we need b to equal -1 so that we get an answer of -1 opposed to if we made a=-1 and c=-1, all outcomes would equal 1)
-1²=1
-1³=-1
1⁴= 1
since 1 is the largest possible outcome and -1 is the lowest possible outcome you should subtract the two
1-(-1) = 1+1 = 2
The answer should be D: 2
hoped this helped at all!
3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
The droplet's horizontal velocity will be:
V/2.
So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6
Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =
The answer is 2(3x-y)+5(x+2y).