Answer:
The numbers are
22 and 23 to solve a problem like this, we need to read and define as we go. Let me explain. So we know that there are two consecutive integers. They can be
x and x+1
. Since their consecutive, one has to be 1
number higher (or lower) than the other. Ok, so first we need "seven times the larger"( 7x+1)
Next, we need to "minus three times the smaller" 7(x+1)−3x
Is equal to " 957(x+1)−3x=95
Alright! There's the equation, now we just need to solve for x! First we are going to get everything on one side and distribute the 7=7x+7−3x−95=4x−88
Pull out a
=4(x−22)Now that we have two terms, we can set them both equal to
0 and solve.4≠0
This can never be true, lets move to the next term (x−22)=0x=
22 That's it! So your two consecutive numbers are
22
Answer:
15
Step-by-step explanation:
-(1)x + 5 = 10
-5 -5
----------------
-x = 5
+1 +1
----------
x = 6
A is the answer if you multiply 474 by 2 and keep multiplying you will get the same numbers as letter A
Answer:
13n +9
Step-by-step explanation:
There is nothing to solve. We can simplify the expression by eliminating parentheses and combining like terms.
7n +6(n +4) -15 . . . . . . given
7n +6n +6(4) -15 . . . . use the distributive property
(7 +6)n +(24 -15) . . . .identify and group like terms
13n +9 . . . . . . . . . . combine like terms
