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2 years ago

If you start off with 1220 and you take away 100 then add 50 how much do you have

Mathematics

2 answers:

irinina [24]2 years ago

8 0

1220 - 100 = 1120

1120 + 50 = 1170

Answer: 1170

Firdavs [7]2 years ago

3 0

Answer:

1170

Step-by-step explanation:

HI hope you have a wonderful day.

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What is the volume of the pyramid in the diagram?

Jlenok [28]

The volume of a pyramid is lwh/3

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2 years ago

PRECALCULUS please help

sergejj [24]

Answer:

Step-by-step explanation:

$f(x) = \frac{2x + 6}{3x} \\ \\ g(x) = \frac{ \sqrt{x} - 8}{3x}$

To find ( f - g)(x) , subtract g(x) from f(x)

That's

$( f - g)(x) = \frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x}$

Since they have a common denominator that's 3x we can subtract them directly

That's

$\frac{2x + 6}{3x} - \frac{ \sqrt{x} - 8}{3x} = \frac{2x + 6 - ( \sqrt{x} - 8) }{3x} \\ = \frac{2x + 6 - \sqrt{x} + 8 }{3x} \\ = \frac{2x - \sqrt{x} + 6 + 8 }{3x}$

We have the final answer as

Hope this helps you

6 0

3 years ago

Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i

Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) $\frac{20i+21}{29}$

Step-by-step explanation:

We have to perform division

(a) $\frac{1-2i}{2i}$

So after division

$\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1$

(b) We have given expression $\frac{5-2i}{5+2i}$

After rationalizing $\frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}$

After rationalizing

$\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i$

5 0

3 years ago

If the 6th term of an arithmetic progres- sion is 11 and the first term is 1, find the common difference.

Darina [25.2K]

Answer:

Step-by-step explanation:

An arithmetic progression with first term a and common difference d has the following first 6 terms:

a, a + d, a + 2d, a + 3d, a + 4d, a + 5d

We are given a = 1 and a + 5d = 11.

1 + 5d = 11

5d = 10

d = 2

Answer: The common difference is 2.

3 0

1 year ago

Two functions are combined resulting in the function j(x) = –3x2 + 5.

labwork [276]

Answer:

two quadratic functions combined by addition

a linear function and a quadratic function combined by addition

two linear functions combined by multiplication

Step-by-step explanation:

-3x² + 5

(-4x² + 4) + (x² + 1)

-3x² + 5

(-3x² - x) + (x + 5)

-3x² + 5

(sqrt(5) - sqrt(3)x)(sqrt(5) + sqrt(3)x)

7 0

2 years ago