A and D seem to be the only correct ones. Hope this helps
Answer:

Step-by-step explanation:
Let the numbers be x and y
<h3>Given condition:</h3>
x + y = 48 --------(1)
y = 7x -------------(2)
Put Eq. (2) in (1)
x + 7x = 48
8x = 48
Divide 8 to both sides
x = 48/8
<h3>x = 6</h3>
Put x = 6 in Eq. (2)
y = 7 (6)
<h3>y = 42</h3>
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
Let the cost of orange be X and cost of cherry be y
3x + 9y = 78
8x + 4y = 58
Solving equation using elimination method
multiplying eq 1 with 8 and eq 2 with 3
8(3x + 9y ) = 78(8)
3( 8x + 4y) = 3(58)
24x + 72 y = 624
24x + 12y = 174
subtracting,
60 y = 450
y = 7.5
3x + 9(7.5) = 78
3x + 67.5 = 78
3x = 78 - 67.5
3x = 10.5
x = 3.5
<h2>Box of orange = $3.5 </h2><h2>Box of cherry = $7.5</h2>
Explanation
Problem #2
We must find the solution to the following system of inequalities:

(1) We solve for y the first inequality:

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

The solution to this inequality is the set of all the points (x, y) over the line:

This line has:
• slope m = 3/2,
,
• y-intercept b = -2.
(2) We solve for y the second inequality:

The solution to this inequality is the set of all the points (x, y) below the line:

This line has:
• slope m = -1/3,
,
• y-intercept b = 2.
(3) Plotting the lines of points (1) and (2), and painting the region:
• over the line from point (1),
,
• and below the line from point (2),
we get the following graph:
Answer
The points that satisfy both inequalities are given by the intersection of the blue and red regions: