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Alex_Xolod [135]
3 years ago
10

If the switches at 2, 3, 4, and 5 are independently closed or open with probabilities 0.1 (for closed) and 0.9 (for open), what

is the probability of a closed path between the input line on the left and the output line on the right
Mathematics
1 answer:
leonid [27]3 years ago
5 0

Complete Question

The Complete Question is attached below

Answer:

P(X)=0.0163

Step-by-step explanation:

From the question we are told that

Probability of open P(x)O=0.9

Probability of open P(x)C=0.1

Generally the equation for Probability of a closed path between the input line on the left and the output line on the right is  mathematically given by

 P(X)=(P(3\&5)C*P(2\&4)C)+(P(2\&4)O+P(2\&4)C*P(1\&3)O)+(P(1\&3)C-P(3\&5)C*P(2\&4)C)

 P(X)= 0.1*0.1*(0.1*0.1+0.9*0.9 ) + 0.1*0.1*(0.9*0.9 + 0.1*0.1) - 0.1*0.1*0.1*0.1

 P(X)=0.0163

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Discrete Mathematics I
faust18 [17]

ANSWER



The general solution is 86+280n, where n is an  integer



<u>EXPLANATION</u>



In order  to solve the linear congruence;



33x \equiv 38(mod\:280)



We need to determine the inverse of 33 (which is a Bézout coefficient for 33).



To do that we must first use  the Euclidean Algorithm to verify the existence of the inverse by showing that;



gcd(33,\:280)=1



Now, here we go;



280=8\times33+16



33=2\times 16+1



16=2\times 8+0



The greatest common divisor is the last remainder before the remainder of zero.



Hence, the gcd(33,\:280)=1.



We now express this gcd of 1 as a linear combination of  33 and 280.



We can achieve this by making all the non zero remainders the subject and making a backward substitution.



1=33-2\times 16--(1)



16=280-33\times8--(2)



Equation (2) in equation (1) gives,



1=33-2\times (280-8\times33)



1=33-2\times 280+16\times33



1=17\times33-2\times 280



The above linear combination tells us that  17 is the inverse of 33.



Now we multiply both sides of our congruence relation by 17.



17\times 33x \equiv 17\times 38(mod\:280)



This implies that;



x \equiv 646(mod\:280)



x \equiv 86.



Since this is modulo, the solution is not unique because any integral addition or subtraction of the modulo (280 in this case) produces an equivalent solution.



Therefore the general solution is,



86+280n, where n is an  integer

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