Well, remember we can't take the square root of a negative
so we see that we have
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input
for y1
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7
An = a1 r^(n-1)
here a1 = 6 and r = 3 so
a7 = 6 * 3^(7-1)
= 4374 answe
Answer:
Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.
Step-by-step explanation:
Given:
First 4 test scores = 87%, 92%, 76%,89%
Average targeted = 80%
We need to find the minimum score she needs to make on fifth test to achieve average of at least 80%.
Solution:
Let the minimum score she needs to make in fifth test be 'x'.
Total number of test = 5
Now we know that;
Average is equal to sum of all the scores in the test divided by number of test.
framing in equation form we get;
Multiplying both side by 5 we get;
Subtracting both side by 344 we get;
Hence Sandra need to score at least <u>56%</u> in her fifth test so that her average is 80%.
The answer is the second one
Answer: L, J, K
Step-by-step explanation:
L, J, and K are collinear because they all lie on the same line.