Answer:
a 6,3 b 2,3 c 2,-1 d 6,-1
Step-by-step explanation:
flip the signs
Answer:
November 13
Step-by-step explanation:
Following dates are given
On November 10 = Merchandise ordered
Date of an invoice prepared, dated and mailed = November 13
Date when the merchandised received by the buyer = November 18
So, the credit period begins when the invoice is prepared, dated and the mailed by the seller to the buyer as it is the evidence of that the merchandise is ordered
Hi there
Total paid
31×12
=372
finance charge
372−295
=77
Hope it helps
Answer:
24: x = 31
25: x = 15
Step-by-step explanation:
Remark
24 is supplementary which means that the two angles add to 180o which is on the right hand side of the equation
25 is complementary which means that the two angles add to 90o which is on the left hand side of the equation
Twenty Four
3x + 31 +2x - 6 = 180 Collect the like terms
3x +2x + 31 - 6 = 180 Do the adding and subtracting.
5x + 25 = 180 Subtract 25 from both sides
5x + 25 - 25 = 180 - 25
5x = 155 Divide by 5
x = 155/5
x = 31
Check
3x + 31 = 3*31 + 31
3x + 31 = 93 + 31
3x + 31 = 124
2x - 6 = 2*31 - 6 = 62 - 6 = 56
Total 124 + 56 = 180 as it should.
Twenty Five
Equation
3x+ 4x - 15 = 90
Solution
7x - 15 = 90 Like terms have been collected on the left.
7x = 90 + 15 15 was added to both sides
7x = 105 Divide by 7
x = 15 I'll leave the check to you
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Population mean (μ) = 2.55
Population standard deviation (σ) = 0.5
Sample size (n) = 30
Sample mean (x) = 2.76
α = 0.05
STEP 1:
Stress score in general executive (s1)
Stress score in exercising executive (s2)
Null : s1 = s2
Alternative : s1 < s2
STEP 2:
Shape of distribution = normal
Population mean (μ) = 2.55
Population standard deviation (σ) = 0.5
Sample size (n) = 30
Sample mean (x) = 2.76
α = 0.05
Decision rule :
α = 0.05 which corresponds to a t score (t0) ;
df = n - 1 = 30 - 1= 30 at 0.05 = 1.699
If :
(Test statistic (t) > t0) ; reject the Null
(right tailed test)
Test statistic (t) :
(x - μ) / (σ/√n)
(2.76 - 2.55) / (0.5/√30)
0.21 / 0.0913
= 2.30
t > t0
2.30 > 1.699
t is more extreme than t0
Hence, reject the null at α = 0.05
