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Misha Larkins [42]
3 years ago
10

Matt plans to put concrete on a rectangular portion of his driveway. The portion is 8 feet long and 4 inches high. The price of

concrete is $98 per cubic yard. The total cost of the concrete Matt needs is $58.07. Which of the following is closest to the width of the portion of the driveway on which Matt plans to put concrete?
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
7 0
First of all, you know that 1 cubic yard = 27 feet. Then you have to find the total amount of cubic yards. 1 cubic yard = $98. We have to use a variable that has to be width or x. Now you can solve for x. You should get x "cubic yard" = $58.07 *Not the answer. 1/x = 98/58.07 ≈ .5925. Next, convert to cubic feet. We know all essential dimensions so now we can solve. 1/.5925 = 27/x. Using this information we can assume that x = 15.99 cubic feet. Lastly, do L*W*H = 16. W*8*(1/3) = 16 so W = 48/8 which 6 feet. *W = 6 ft (Hope this helps!)
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Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school n_1 = 42

sample size for the second school n_2  = 34

so 16 out of 42 i.e x_1 = 16 and 18 out of 34 i.e x_2 = 18 have ear infection.

the proportion of students with ear infection Is as follows:

\hat p_1 = \dfrac{16}{42} = 0.38095

\hat p_2 = \dfrac{18}{34}  =  0.5294

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level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

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S.E = \sqrt{ \dfrac{  0.447368 *  0.552632}{ 42} +  \dfrac{ 0.447368 *  0.447368}{34} }

S.E = \sqrt{ \dfrac{  0.2472298726}{ 42} +  \dfrac{ 0.2001381274}{34} }

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Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

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