Answer:
See Explanation
Step-by-step explanation:
According to the Question,
Given that, A retired couple has up to $50,000 to invest. As their financial adviser, you recommend that they place at least $35,000 in Treasury bills yielding 1% and at most $10,000 in corporate bonds yielding 3%.
Therefore,
Let, x be the amount of money invested in Treasury bills
y be the amount invested in corporate bonds
Thus, the system of equations of linear inequalities is
x + y ≤ 50000
x ≥ 35000
0 ≤ y ≤ 10000
For, the graph of the system of equations of linear inequalities describes the possible amounts of each investment.
(Please find in the attachment)
X=-7y+34
x+7y=32
To begin with make the two problems the same kind of problem. By adding 7y on both sides for the first problem.
x+7y=34
x+7y=32
So the correct answer would be no solution because it's the same problem and it can't equal to different answers.
Answer:
97 and 1/8
Step-by-step explanation:
(4 + 7 + 5 + 5 + 2) + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)
23 + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)
23 + 74 1/8
97 and 1/8
Since both C & D are parallel, angle 2 is a corresponding angle to the angle of 108 degrees, so angle 2 is also 108 degrees
Answer: 5 km walking and 30 km by bus
Step-by-step explanation:
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?
walking - 5km/h bus - 60km/h
distance walking - d₁ distance bus - d₂
time walking - t₁ time bus - t₂
d₁ + d₂ = 35
t₁ + t₂ = 1.5
v = d/t
vwalking = d₁/t₁
5 = d₁/t₁ ⇒ d₁ = 5t₁
vbus = d₂/t₂
60 = d₂/t₂ ⇒ d₂ = 60t₂
d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35
_________________________
5t₁ + 60t₂ = 35
t₁ + t₂ = 1.5 (*-5)
5t₁ + 60t₂ = 35
-5t₁ -5t₂ = -7.5 (+)
__________________________
55t₂ = 27.5
t₂ = 27.5/55 = 0.5 h
t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h
d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km
d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km