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Anton [14]
2 years ago
9

Cheryl had 22 charms. She used C charms to make a bracelet then she went to the store and bought 14 more charms. Now she has 25

charms. How many charms did Cheryl use to make the bracelet
Mathematics
2 answers:
antiseptic1488 [7]2 years ago
8 0

Answer:

She used 11 charms.

Step-by-step explanation:

25-14=11

22-11=11

Lyrx [107]2 years ago
8 0

Answer: She used 11 charms.

Step-by-step explanation:

The equation to find the answer is 22-C+14=25. You would minus 14 from both sides, leaving you with 22-C=11. 22-11=11, so your answer is 11 charms. Hope this helped!

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A popular magazine tests cars and trucks for mileage on the road and around the city. The magazine reports that the most common
Llana [10]

It shows that the values of the mileages are close to 24 mpg. Hence statistics refes 24 as the mean.

<h3>Mean of a data.</h3>

Mean is one of the measure of dispersion and is the avearage of a set of data.

According to the question, the magazine reports that the most common gas mileage was 24 mpg. This shows that reports have published several gas mileages for cars and truck and the average of this mileage is 24mpg

It shows that the values of the mileages are close to 24 mpg. Hence statistics refes 24 as the mean.

Learn more on mean here: brainly.com/question/14532771

#SPJ1

4 0
2 years ago
1 point
weeeeeb [17]

Answer:

The answer is 0.71 per ounce.

Step-by-step explanation:

You can use proportions to solve this.

\frac{89.95 dollars}{64lb} = \frac{1 dollar}{x} \\64 * 1 = 64\\89.95 * x = 89.95x\\\\\frac{64}{89.95} = \frac{89.95x}{89.95}\\\\0.7115063924 = x\\Which when rounded to the nearest hundredths is:\\0.71

5 0
2 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
Help needed due today
kobusy [5.1K]

Answer:

1 1/4 inches deeper

Step-by-step explanation:

3 0
2 years ago
Solve five and three sixths minus two and one third.
CaHeK987 [17]

Answer:

3 3/18

Step-by-step explanation:

5 3/6-2 1/3

We first need to turn our mixed numbers into fractions by multiplying the while number by the denominator, then adding the numerator. When we do this, 5 3/6 turns into 33/6 and 2 1/3 turns into 7/3. Now we have this:

33/6-7/3

Now we need to find the Least common multiple of the denominators in order to find our common denominator, which in this case is 6. 33/6 already has a denominator of 6, so we do not need to do anything to it. To give a denominator of 6 to 7/3, however, we must multiply by 2, giving us this:

33/6-14/6

Now we can subtract the numerators.

19/6

To turn this back into a mixed number, we divide 19 by 6, which gives us 3 with a remainder of 1. Therefore, our answer is 3 1/6. This is an equivalent fraction to the fourth answer, 3 3/18.

HTH :)

4 0
3 years ago
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