The probabilty is 6/26. i thnk im not really good with this stuff
We have that
t²<span> – 81
</span>
we know that
A difference of two perfect squares, <span> (A</span>²<span> - B</span>²)<span> </span><span>can be factored into </span><span> (A+B) • (A-B)
</span> let
A²-------> t²
B²-------> 9²
then
(t² – 9²)------->(t+9)*(t-9)
the answer is
(t+9)*(t-9)
You ANSWER : x=10 Let's solve !
Explanation : Let's solve your equation step-by-step.
1
3
(
2
x
−
8
)
=
4
Step 1: Simplify both sides of the equation.
1
3
(
2
x
−
8
)
=
4
(
1
3
)
(
2
x
)
+
(
1
3
)
(
−
8
)
=
4
(Distribute)
2
3
x
+
−
8
3
=
4
Step 2: Add 8/3 to both sides.
2
3
x
+
−
8
3
+
8
3
=
4
+
8
3
2
3
x
=
20
3
Step 3: Multiply both sides by 3/2.
(
3
2
)
*
(
2
3
x
)
=
(
3
2
)
*
(
20
3
)
x
=
1
Answer:
her score is lower after removing the highest and lowest value
just took the test
Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean 
and a standard deviation 
. For a value x we compute the z-score as 
, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
