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Anton [14]
2 years ago
9

Cheryl had 22 charms. She used C charms to make a bracelet then she went to the store and bought 14 more charms. Now she has 25

charms. How many charms did Cheryl use to make the bracelet
Mathematics
2 answers:
antiseptic1488 [7]2 years ago
8 0

Answer:

She used 11 charms.

Step-by-step explanation:

25-14=11

22-11=11

Lyrx [107]2 years ago
8 0

Answer: She used 11 charms.

Step-by-step explanation:

The equation to find the answer is 22-C+14=25. You would minus 14 from both sides, leaving you with 22-C=11. 22-11=11, so your answer is 11 charms. Hope this helped!

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For the following set of 20 numbers:
patriot [66]

Answer:

I cannot answer all of this, so I will only answer what I can:

Q1: 13

Q3: 22.5

IQR: 13.5

IQR(1.5): 20.25

Q3 + IQR(1.5) = 43

Q1 - IQR(1.5) = -7.25

I don't know if my calculations are all right but I hope this helps! :)

4 0
2 years ago
PLS HELP I HAVE TO DO GYM OR I WILL GET A BAD GRADE HELP I NEED THIS DONE
zlopas [31]

Answer:

1. Yes, 34+12=46

2.No, 22-9=13

3. Yes, 6*9=54

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4 0
3 years ago
Mr Lim read 3 books in 2 hours. He took the same amount of time to read the first two books. He took 15 minutes longer to read t
Naya [18.7K]
He took 75 minutes to read the third book.
5 0
3 years ago
PLZ HELP ASAP ANGLE BISECTOR THEOREM
ycow [4]
Angle bisector theorem:
CD/DB=AC/AB
REeplacing the known values:
CD/4=5.6/5.1
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CD=22.4/5.1
CD=4.392156863
Rounded to one decimal place:
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7 0
3 years ago
The annual energy consumption of the town where Camilla lives in creases at a rate that is onal at any time to the energy consum
boyakko [2]

Answer:

6.575 trillion BTUs

Step-by-step explanation:

<em>Let represent the annual energy consumption of the town as E</em>

<em>The rate of annual energy consumption *  energy consumption at time past</em>

<em>dE/dt * E</em>

<em>dE/dt =K</em>

<em>k = the proportionality constant</em>

<em>c= the integration constant</em>

<em>(dE/dt=) kdt</em>

<em>lnE = kt + c</em>

<em>E(t) = e^kt+c ⇒ e^c e^kt  e^c is a constant, and e^c = E₀</em>

<em>E(t) = E₀ e^kt</em>

<em>The initial consumption of energy is E(0)=4.4TBTU</em>

<em>set t = 0 then</em>

<em>4.4 = E₀ e⇒ E₀ (1) </em>

<em>E₀ = 4.4</em>

<em>E (t) = 4.4e^kt</em>

<em>The consumption after 5 years is t = 5, e(5) = 5.5TBTU</em>

<em>so,</em>

<em>E(5) = 5.5 = 4.4e^k(5)</em>

<em>e^5k = 5/4</em>

<em>We now take the log 5kln = ln(5/4)</em>

<em>5k(1) = ln(5/4)</em>

<em>k = 1/5 ln(5/4) = 0.04463</em>

<em>We find  the town's annual energy consumption, after 9 years</em>

<em>we set t=9  </em>

<em>E(9) = 4.4e^0.04463(9)</em>

<em>= 4.4(1.494301) = 6.5749TBTUs</em>

<em>Therefore the annual energy consumption of the town after 9 years is </em>

<em>= 6.575 trillion BTUs</em>

<em />

3 0
3 years ago
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