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3 years ago

What is the surface area of the cylinder with height 5 ft and radius 3 ft? Round your answer to the nearest thousandth

Mathematics

1 answer:

BabaBlast [244]3 years ago

8 0

Answer:

150.8ft²

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·5+2·π·32≈150.79645ft²

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If a plumber charges $80/hr for labor, w, and $60 for parts, write an equation that would describe the scenario of hiring a plum

Nadusha1986 [10]

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3 years ago

Simplify the expression using the distributive property 9(4y-7)

lbvjy [14]

Multiply what is outside the parenthesis by what is inside.
the answer is 36y-63
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3 years ago

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Lillian and Isabella went shopping for school supplies. Lillian found her favorite notebook on sale so she bought three of the e

ASHA 777 [7]

Answer:

Each girl had $7.50 when they arrived.

Step-by-step explanation:

We have to figure out what c (cost of each notebook) is first before we find out how much money each girl had. We also know they have the same money, so both sides are connected. The equation should be: 3x = x + 5.

3x = x + 5

First, subtract x from both sides. This cancels out the addition by x.

3x - x = 5

Now, subtract x from 3x. This equals 2x.

2x = 5

To cancel out the multiplication by 2, divide both sides by 2.

x = 5/2

Lastly, divide 5 by 2 to get 2.5.

x = 2.5

Substitute x for 2.5 in the earlier equation (3x = x + 5)

3(2.5) = 2.5 + 5

First, multiply 3 by 2.5 to get 7.5.

7.5 = 2.5 + 5

Add 2.5 to 5 to get 7.5.

7.5 = 7.5

Both sides are equal so we have our answer. So, both girls had $7.50 when they arrived at the store.

4 0

3 years ago

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

Step-by-step explanation:

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago

Find the slope of the line that passes through the points (-8, -3) and (2, 3)

kherson [118]

Answer:

The slope is 3/5.

Step-by-step explanation:

Slope formula:

$\displaystyle \frac{y_2-y_1}{x_2-x_1}=\frac{rise}{run}$

$\displaystyle \frac{3-(-3)}{2-(-8)}=\frac{6}{10}=\frac{6\div2}{10\div2}=\frac{3}{5}$

Therefore, the slope is 3/5, and the correct answer is 3/5.

4 0

3 years ago

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