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Inessa05 [86]
3 years ago
7

What is the surface area of the cylinder with height 5 ft and radius 3 ft? Round your answer to the nearest thousandth

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

150.8ft²

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·5+2·π·32≈150.79645ft²

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If these are diving fractions with these then it is 3 1/2 if they are not fractions then it is 0.22 
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A rectangular school banner has a length of 44 inches, a perimeter of 156 inches, and an area of 1,496 square inches. the cheerl
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A rectangular school banner has a length of 44 inches, a perimeter of 156 inches, and an area of 1,496 square inches. the cheerleaders make signs similar to the banner. the length of a sign is 11 inches. First solve the width of the rectangle:

1496 sq in/ 44 = 34 in

So the sign has also a width of 34 in and a length of 11 so the area is 34*11 =374 sq in

<span>The perimeter is (34*2) +(11*2) =90 in</span>

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P(m)=m/5+8
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M(p) = 5p-40 (apex) ....

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A phone company charges 0.1 per minutes talked and additional $24 for services each month. Write the liner function C(n) where n
ella [17]

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the cost of talking for 15 minutes would be $1.5

15x0.1=1.5

for $50 you could talk for 500 minutes.

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6 0
3 years ago
Please solve these questions for me. i am having a difficult time understanding.
s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

\angle AED = \angel BEC ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

\angle ABC = 90^{\circ}

In ΔDBC

BC=DC (Given)

So,\angle CDB=\angle DBC(Opposite angles of equal sides are equal)

So,\angle CDB=\angle DBC=x

So,\angle CDB+\angle DBC+\angle BCD = 180^{\circ} (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So,\angle CDB=\angle DBC=x = 65^{\circ}

Now,

\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90

So,\angle ABD=90-x=90-65=25^{\circ}

In ΔABD

AB = BD (Given)

So,\angle BAD=\angle BDA(Opposite angles of equal sides are equal)

So,\angle BAD=\angle BDA=y

So,\angle BAD+\angle BDA+\angle ABD = 180^{\circ}(Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0
3 years ago
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