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DIA [1.3K]
3 years ago
7

A restaurant's small salt shakers contain 0.6 ounces of salt. It's large shakers hold twice as much. The shakers are filled from

a container that has 18.6 ounces of salt. If 8 large shakers are filled, how many small shakers can be filled with the remaining salt?

Mathematics
2 answers:
Ratling [72]3 years ago
8 0
First you have to multiply the 0.6 of the small shakers times two which gives us 1.2 the amount of salt of the large shakers. divide the 18.6 by 1.2 which is 15.5 the amount going into the 8 shakers. Then subtract 15.5 from 18.6 which gives us 3.1. Then you divide that by 0.6 = 5. 5 small shakers can be filled with the remaining salt.
g100num [7]3 years ago
8 0

<h2>15 small shakers can be filled with the remaining salt.</h2>

<h3>Further explanation</h3>

Order of Operations in Mathematics follow this following rule :

  • Parentheses
  • Exponents
  • Multiplication and Division
  • Addition and Subtraction

This rule is known as the PEMDAS method.

In working on a mathematical problem, we first calculate operation that is in parentheses, follow by exponentiation, then multiplication or division, and finally addition or subtraction.

Let us tackle the problem!

<em>A restaurant's small salt shakers contain 0.6 ounces of salt.</em>

\texttt{Small Shaker's Capacity} = S = 0.6 ~ \texttt{ounces}

<em>Its large shakers hold twice as much.</em>

\texttt{Large Shaker's Capacity} = L = 2 \times \texttt{Small Shaker's Capacity}

\texttt{Large Shaker's Capacity} = L = 2 \times 0.6 ~ \texttt{ounces}

\texttt{Large Shaker's Capacity} = L = 1.2 ~ \texttt{ounces}

<em>The shakers are filled from a container that has 18.6 ounces of salt.</em>

\texttt{Total Mass of Salt} = 18.6 ~ \texttt{ounces}

<em>If 8 large shakers are filled , then</em>

\texttt{Total Mass of Salt} = (8 \times L) + (\texttt{Number of Small Shakers} \times S)

18.6 = (8 \times 1.2) + (\texttt{Number of Small Shakers} \times 0.6)

18.6 = 9.6 + (\texttt{Number of Small Shakers} \times 0.6)

18.6 - 9.6 = (\texttt{Number of Small Shakers} \times 0.6)

9 = (\texttt{Number of Small Shakers} \times 0.6)

\texttt{Number of Small Shakers} = 9 \div 0.6

\texttt{Number of Small Shakers} = \boxed {15}

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Order Of Operations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent

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