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4vir4ik [10]
3 years ago
15

(8х + 2)(7х^2 + 6x - 7) Find the product

Mathematics
1 answer:
igomit [66]3 years ago
4 0
The product is 56x^3+62x^2-44x-14
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When Sally was a Freshman, her soccer team had 13 players. By her senior year, Sally’s soccer team grew to 17. What is the perce
ra1l [238]

Answer:

about 31 percent

Step-by-step explanation:

5 0
3 years ago
A rope is tied to the bottom of a hot air balloon ad shown below The rope makes an angle of 35 with the ground and is 75 ft long
damaskus [11]

Answer:

The answer to your question is 43 ft

Step-by-step explanation:

Data

angle = Ф = 35°

length = 75 ft

height = ?

Process

To solve this problem, use trigonometric functions. The trigonometric function that relates the Opposite side (height) and the hypotenuse (length) is sine.

               sin Ф = Height / length

-Solve for height

                height = length x sin Ф

-Substitution

                height = 75 x sin 35

-Simplification

                height = 75 x 0.574

-Result

                 height = 43 ft

6 0
3 years ago
7. Given f(x) = 6(1 - x) +11, what is the value of f(8) ?
enot [183]

Answer:

f(8)=-31

Step-by-step explanation:

since 8 replaces x in f(x), x should be substituted as 8 in the expression. From there, after you substitute, it becomes 6(1-8)+11. Simplifying that expression is now 6(-7)+11. Multiply 6 and -7, you get -42. -42+11=-31. I hope this helps :)

6 0
3 years ago
Allyson and Adrian have decided to connect their ankles with a bungie cord; one end is tied to each person's ankle. The cord is
BARSIC [14]

Answer: 5.5 seconds

Step-by-step explanation:

30=5/4 ×(-20) + 10t

30 =-25 +10t

10t=55

t=5.5seconds

The cord will first touch the corner of the building after 5.5secs

3 0
3 years ago
G(x) = -2x^3 – 15x^2 + 36x
shusha [124]

Consider the function G(x) = -2x^3 - 15x^2 + 36x. First, factor it:

G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).

The x-intercepts are at points \left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).

1. From the attached graph you can see that

  • function is positive for x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);
  • function is negative for x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).

2. Since

G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x) the function is neither even nor odd.

3. The domain is x\in (-\infty,\infty), the range is y\in (-\infty,\infty).

8 0
3 years ago
Read 2 more answers
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