Answer:
10 losses
Step-by-step explanation:
Here, we want to get the greatest possible number of games the team lost
Let the number of games won be x
Number drawn be y
Number lost be z
Mathematically;
x + y + z = 38
Let’s now work with the points
3(x) + 1(y) + z(0) = 80
3x + y = 80
So we have two equations here;
x + y + z = 80
3x + y = 80
The greatest possible number of games lost will minimize both the number of games won and the number of games drawn
We can have the following possible combinations of draws and wins;
26-2
25-5
24-8
23-11
22-14
21-17
21-17 is the highest possible to give a loss of zero
Subtracting each sum from 38, we have the following loses:
10, 8, 6, 4, 2 and 0
This shows the greatest possible number of games lost is 10
It is D, because you have to get the denomenator"s equal so 9 times 4 is 36 and you take the numerator's and times by the other's denominator then subtract them to get 5/36
The answer is 800000 because if the number before the number you want to round is 4 or less the number stays the same and all tue other numbers get chnges to 0's
Answer:
20
15
11
Step-by-step explanation:
Answers off Edgenuity
$ 45 is ur y value and 180 is ur x value....slope = y/x
so ur slope is : 45/180 = 0.25 or 1/4
