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3 years ago

Can someone please explain to me how to find y-intercept on a graph? I AM SO CONFUSED PLEASE HELP!!!

1 answer:

6 0

The y intercept is the point where the line passes through on the y-axis.for example on the graph that I showed we can see how the line passes through the 1 on the y-axis. This means 1 is our y-intercept. If you are still confused let me know lol

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Abbey purchased a house using a fixed rate mortgage. The annual interest rate is 4.2% compounded monthly for 20 years. The mortg

Butoxors [25]

I GOT $9870.

4.2 % OF $235,000 IS $9870.

6 0

3 years ago

Chip earns a base salary of 500 per month as a Salesman in addition to the salary earns 90 per product that he sells if his goal

Lerok [7]

Answer:idk

Step-by-step explanation:

6 0

3 years ago

What two numbers have a sum of -7 and a difference of 14?

Ksivusya [100]

Answer:

The sum of two numbers is 14 and their difference is 10

Step-by-step explanation:

"2 numbers (x and y)

x+y = 14

and x-y + 10

If you each equation by positive 2, one gets 2x+2y = 28 and 2x-2y = 20

The 'y-terms' cancel out or equal zero when adding, so 4x = 48, divide by 4 on each side and x or the first number equals 12.

Plug 12 back into the equation for 'x' and subtract 12 on both sides so that y=2

The difference of 12-2=10 and the addition of 12 and 2 equals 14"

hopes this helps

7 0

3 years ago

Read 2 more answers

What is greater one seventh or one nineth

Anton [14]

Method 1:

Look at the picture.

$\dfrac{1}{7}$ is greater than $\dfrac{1}{9}$

$\boxed{\dfrac{1}{7}>\dfrac{1}{9}}$

Method 2:

Find the common denominator:

multiples of 7: 0, 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ...

multiples of 9: 0, 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, ...

63 = 7 · 9

$\dfrac{1}{7}=\dfrac{1\cdot9}{7\cdot9}=\dfrac{9}{63}\\\\\dfrac{1}{9}=\dfrac{1\cdot7}{9\cdot7}=\dfrac{7}{63}$

$\dfrac{9}{63} > \dfrac{7}{63}$

therefore

$\dfrac{1}{7} > \dfrac{1}{9}$

3 0

3 years ago

Read 2 more answers

These ordered pairs, {(2,4) (3,6) (4,8) (5,10)}, are a function. True False

ki77a [65]

Answer:

True

Step-by-step explanation:

In order for a relation (a set of ordered pairs) to be considered a function, every value in the domain (the set of all the first numbers in the pair) is associated with one value in the range (the set of all second numbers in the pair). This is easiest to see visually. Our domain is the set {2, 3, 4, 5} and our range is the set {4, 6, 8, 10}, and we can visualize the ordered pair (2, 4) as an "arrow" starting a 2 in the domain and ending at 4 in the range. When seen this way, a relation is a function if every value in the domain only has one arrow coming out of it. We can see from the attached picture that the ordered pairs in the problem are a function, so this statement is true.

8 0

4 years ago